A column 500 mm x 500 mm square is supported by a 3.5 m x 3.5 m isolated spread footing. The column carries a dead load of 1200 kN and a live load of 1000 kN. The total depth of the footing is 550 mm with steel cover of 100 mm. Use NSCP 2001 provisions. Determine the punching shear stress at ultimate loads. A 1830.00 kPa 2154.11 kPa 1566.48 kPa D 1331.52 kPa

A column 500 mm x 500 mm square is supported by a 3.5 m x 3.5 m isolated spread footing. The column carries a dead load of 1200 kN and a live load of 1000 kN. The total depth of the footing is 550 mm with steel cover of 100 mm. Use NSCP 2001 provisions. Determine the punching shear stress at ultimate loads. A 1830.00 kPa 2154.11 kPa 1566.48 kPa D 1331.52 kPa

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter16: Soil Bearing Capacity For Shallow Foundations

Section: Chapter Questions

Problem 16.15P: Refer to Problem 16.13. Design the size of the footing using the modified general ultimate bearing...

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A rectangular footing (base = 1.76 m., length = 5.83 m.) has its bottom 3.06 m. below the ground surface. Unit weight of soil is 19.07 kn/m3, unconfined compressive strength = 156 kPa. Use angle of internal friction = 10° (Nc = 9, Nq = 2.5, = 1.2). Compute the allowable load that the footing could carry. Use FS = 2.8. Round off to the nearest whole number.
A 1.65m wide square footing is embedded 1.81m beneath the ground surface. The soil about the ground water table has a unit weight of 16.79 kN/m3, saturated unit weight of 19.86 kN/m3, and an unconfined compressive strength of 134 kPa (hint: half of this is the cohesion). The angle of internal friction is 18 degrees. The load acting on the column are given below. Assume a plan view where B is parallel to x-axis and L is parallel to the y-axis Vertical axial load = 256kNMy = 65kNmMx = 40kNmThe groundwater table is 0.65m above the base of the footing. The factor of safety is 3.0. The Meyerhof bearing capacity factors are given below: What is the net allowable load (kN) of the footing? 934.459 1582.939 None of the choices 857.933 1058.385 847.372 Please answer this asap. For upvote. Thank you very much
A 1.65m wide square footing is embedded 1.81m beneath the ground surface. The soil about the ground water table has a unit weight of 16.79 kN/m3, saturated unit weight of 19.86 kN/m3, and an unconfined compressive strength of 134 kPa (hint: half of this is the cohesion). The angle of internal friction is 18 degrees.The load acting on the column are given below. Assume a plan view where B is parallel to x-axis and L is parallel to the y-axis Vertical axial load = 256kN My = 65kNm Mx = 40kNm The groundwater table is 0.65m above the base of the footing. The factor of safety is 3.0. The Meyerhof bearing capacity factors are given below: What is the cohesion shape factor \lambda_{cs}λcs? 1.147 None of the choices 1.189 1.379 1.259 1.444 Please answer this asap. For upvote. Thank you very much
A 1.65m wide square footing is embedded 1.81m beneath the ground surface. The soil about the ground water table has a unit weight of 16.79 kN/m3, saturated unit weight of 19.86 kN/m3, and an unconfined compressive strength of 134 kPa (hint: half of this is the cohesion). The angle of internal friction is 18 degrees.The load acting on the column are given below. Assume a plan view where B is parallel to x-axis and L is parallel to the y-axis Vertical axial load = 256kN My = 65kNm Mx = 40kNm The groundwater table is 0.65m above the base of the footing. The factor of safety is 3.0. The Meyerhof bearing capacity factors are given below: What is the difference between the allowable bearing capacity and the maximum bearing pressure in kPa? 386.079 None of the choices 387.161 388.515 335.987 327.928 Please answer this asap. For upvote. Thank you very much
A 1.65m wide square footing is embedded 1.81m beneath the ground surface. The soil about the ground water table has a unit weight of 16.79 kN/m3, saturated unit weight of 19.86 kN/m3, and an unconfined compressive strength of 134 kPa (hint: half of this is the cohesion). The angle of internal friction is 18 degrees.The load acting on the column are given below. Assume a plan view where B is parallel to x-axis and L is parallel to the y-axis Vertical axial load = 256kN My = 65kNm Mx = 40kNm The groundwater table is 0.65m above the base of the footing. The factor of safety is 3.0. The Meyerhof bearing capacity factors are given below: What is the gross allowable bearing capacity (kPa)? 620.356 570.263 622.791 562.204 None of the choices 621.438 Please answer this asap. For upvote. Thank you very much
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A rectangular footing (base = 5.62m., length = 1.78 m.) has its bottom 3.05 m. below the ground surface. Unit weight of soil is 18.23 kN/m3, unconfined compressive strength = 164 kPa. Use angle of internal friction = 10° (Nc = 9, Nq = 5.6, = 2.1). Compute the allowable load (in kN) that the footing could carry. Use FS = 2. Use stored value. Answer in 5 decimal places.
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