a) Determine the effective stress at the bottom of the layer (Ans. 97.68 kPa) b) If the water table rises to the top of the ground surface, what is the change in the effective stress at the bottom of the clay layer. (Ans. 26.32 kPa)

Q: Problem 1. The water table in a certain deposit of soil is at a depth of 2m below the ground…

A: Saturated unit weight of clay…

Q: Problem 1 Refer to the soil profile in the figure below. Given H= 4m and H=3m; a) Calculate the…

A: Note : Since you have asked multiple questions, we will solve the first question for you. If you…

Q: subject - geotechnical design book - principle of foundation engineering

A: We have the following formula for vertical stress:

Q: Problem 7: The clay stratum shown in the profile below has a total vertical stress of 200 kN/m2 at…

A:

Q: Determine the total stress of the dry sand with the dry unit weight, yd is 16.5 kN/m3 at the depth…

A: Given that: Dry unit weight of sand, γd=16.5 kN/m3                  Depth, where stress is required,…

Q: A sand layer 5 meters high overlies a clay layer that is 6 meters high. Ground water table is at the…

A: Given:- Υsand=17.19 KN/m3Ysatcaly=19.9 KN/m3e0=0.53LL=43Δσ=52.7

Q: A soil stratum has two layers a 4m-thick dry sand underlain by a 5m–thick saturated sand. Dry unit…

A: Given data: γdry=16.21 kN/m3γsat=20.88 kN/m3σ'=104 kPa at the bottom of saturated layer

Q: 6. A uniformly loaded horizontal circular area of radius 3 m is loaded with uniform loading…

A: Finding out vertical stresses.

Q: A5 m-thick clay (Gs = 2.65, water content = 0.28) is overlain by a 4.50m-thick layer of sand (Gs =…

A:

Q: Refer to the soil profile shown. Given H1 = 9.89 m., and H2 = 5.80 m. If the ground water table…

A: Formulae used      Unit weight of soil                     (G + es)× Yw/(1+e)    For dry sand ,s = 0…

Q: Q.3) Detemine the increase in vertical stress at a depth 4 m below point A due to surface loads…

A: Given:- The stresses is given with different magnitude  qs = 100 kN/m2 , qs = 160 kN/m2 , qs = 225…

Q: A soil profile shown has a zone of capillary rise in the sand overlying the clay. In this zone, the…

A:

Q: A submerged clay layer is 15 m thick. Its water content is 54%. The density of the soil particles is…

A: Se= wG   eq 1Since the clay layer is submerged ,S=11×e= 0.54×2.78e=1.50

Q: soil profile consists of a sand layer underlain by a clay layer, as shown. If the degree of…

A:

Q: A soil profile shown has a zone of capillary rise in the sand overlying the clay. In this zone, the…

A:

Q: C 6 m B A 5 m 3 m 6 m 3 m Fiq 23 - Prob 23

A:

Q: Question Attached

A: The void ratio is the ratio of the volume of voids in the soil  The vertical stress determined…

Q: 3. What is the shear strength in terms of effective stress on a plane within a saturated soil mass…

A: Total normal stress (σT) = 295 KN/m2 Pore water pressure (u) = 120 KN/m2 Effective cohesion (c') =…

Q: is at the interface of sand and clay. The unit weight of sand is 17.98 kN/m3, saturated unit weight…

A: Given data- Height of clay layer (h) = 8m Height of sand layer = 5m unit weight of sand = 17.98…

Q: What is the shear strength in terms of effective stress on a plane within a saturated soil mass at a…

A:

Q: At what depth would total the vertical stress in a deep deposit of clay (e = 1.11, Gs = 2.73) be 160…

A:

Q: At what depth would total the vertical stress in a deep deposit of clay (e = 1.1, Gs = 2.74) be 100…

A: Given:Void ratioe =1.1Gs=2.74Ysat2 =G+SeYw1+e           =2.74+1.19.811+1.1…

Q: ) A uniform pressure of 150 kN/m acts on a 3 m*4.5 m rectangular rea. Since the point X is at the…

A: by using westergard theory Qz=wπz2 11+2rz23/2where,w=pointed loadz=depth below the midpointr=any…

Q: Q3: Refer to the soil profile shown in the figure below: a) Calculate the variation in vertical…

A:

Q: A clay layer 4 m thick rests beneath a deposit of submerged sand 8 m thick. The top of the sand is…

A: Given data;

Q: At a lake location, the soil surface is 6 m under the water surface. Samples from the soil deposit…

A: Let the diagram of the lake be as follows:

Q: The water table in soil deposit is 2 m below the ground surface. The soil above the water table has…

A:

Q: A saturated site is underlain by a 5m thick layer of clay with undrained strength = 80 kPa, OCR = 2,…

A: The values given in the question are as follows: The thickness of clay layer(hc)=5 m Undrained…

Q: In a clayey sandy silt deposit, the water table is 3.5 m below the surface, but the sand to a height…

A:

Q: ESSES IN SOIL oblem 4. A 20m thick submerged saturated clay layer has water content of 57%. The…

A: H=20m G=2.84 w=57%

Q: Calculate the total vertical stress (ovo) at the base of the clay (Stratum I)/top of the sand…

A: We are authorized to answer three subparts at a time since you have not mentioned which part you are…

Q: A 3 m-thick sand layer is underlain by a deep bed of clay where the water content is 29%. The water…

A:

Q: . A 5-m clay layer lies beneath an 8-m sand layer. The sand is 3 meters below the water surface.…

A:

Q: A layer of saturated clay 6 m thick is underlain by rock and is subjected to an average increase in…

A:

Q: 1 A point load of 2000 KN is acting at the surface of a thick clay stratum. Compute the vertical…

A: Solution From boussinesq's equation, σz = IbQz2 Ib = 32π1+rz252 Substituting, z= 1m to 10 m and r=…

Q: 2. At what depth would total the vertical stress in a deep deposit of clay (e 1.1, G, 2.74) be 100…

A: Given data: Vertical stress (σ) = 100 kpa void ratio (e) = 1.1 Specific gravity of soil solids (GS)…

Q: SITUATION. A silty sand layer has effective diameter of 5 x 10^-6 m and void ratio of 0.80.…

A:

Q: groundwater table rise to decrease the effective stress by 15KN/m^2 at the bottom of the clay layer?

A:

Q: A clay layer 5.61 m. thick rests beneath a deposit of submerged sand 6.16 m. thick. The top of the…

A:

Q: A point load of 500 KN is applied at the ground level. Plot the lateral variation of the vertical…

A: Q=500kN

Q: Problem 1. The water table in a certain deposit of soil is at a depth of 2m below the ground…

A: To find total stress, pore water pressure and effective stress at a depth of 8m

Q: . Three point loads, 19000, 20000 and 18000kN, act in line 8 m, 6m apart near the surface of a soil…

A: Given three point loads that are 8m and 6m apart near the surface of soil mass. It is required to…

Q: a sand layer 9 meters highoverlies a clay layer that is 5 meters high. ground water table is at the…

A:

Q: Problem 6 From the soil profile shown, 4.6 m Ground water table Clay e = 0.9 3.6m Gs = 2.75 1.…

A: Total stress = effective stress + neutral stress  σ = σ' + u

Q: stratum has two layers a 4m-thick dry sand underlain by a 5m–thick saturated sand. Dry unit weight…

A: To find total stress at bottom of soil stratum

Q: A soil profile consists of two layers of soil with clay layer underlying the sand layer. The sand…

A:

Q: 1 points A sand layer 8 meters high overlies a clay layer that is 9 meters high. Ground water table…

A: Given: Thicknesses of sand layer: 8m Thickness of clay layer :9m Unit weight of sand  Unit weight of…

Q: Effective Stress in Soil Problem 1. The water table in a certain deposit of soil is at a depth of 2m…

A:

Q: A dense silt layer has the following properties: e =0.400 D10= 10.0 µm Capillary constant = 0.209…

A: hc=ceD10

Q: 2. A borehole at a site reveals the soil profile shown. Assume Gs = 2.70 for all soil types. a. What…

A: Given data in question  Degree of saturation  Water content  Depths Cappilary saturated To find out…

Methods to Determine Vertical Stress

The load applied to the soil is transferred to the underground. The presence of water at soil pores and solid grains above the soil are the primary components that are responsible for the effective load transfer. Due to the load acting, the internal component of the soil or the underground formations undergoes deformations or a tectonic shift. The amount of deformation depends upon the amount of load acting on the soil surface, which indeed, depends on the weight of everything present above the soil. Due to this, the underground soil element develops internal stresses which try to resist the tectonic changes.