A digital watch battery draws 0.10 milliamperes of current, which is provided by a mercury battery whose net reaction is: HgO(s) + Zn(s) → ZnO(s) + Hg(l) If a partially used battery contains 1.40 g of each of these four substances, for how many hours will the watch continue to run? hint: Determine the limiting reagent in terms of moles. Then multiply by the stoichiometric ratio to determine the number of moles of electrons produced. Then convert moles of electons into Coulombs (Amps*seconds). Then you just need to divide by amps used to find the total number of seconds, and convert to hours.
A digital watch battery draws 0.10 milliamperes of current, which is provided by a mercury battery whose net reaction is: HgO(s) + Zn(s) → ZnO(s) + Hg(l) If a partially used battery contains 1.40 g of each of these four substances, for how many hours will the watch continue to run? hint: Determine the limiting reagent in terms of moles. Then multiply by the stoichiometric ratio to determine the number of moles of electrons produced. Then convert moles of electons into Coulombs (Amps*seconds). Then you just need to divide by amps used to find the total number of seconds, and convert to hours.
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter17: Electrochemistry And Its Applications
Section: Chapter Questions
Problem 34QRT: In principle, a battery could be made from aluminum metal and chlorine gas. (a) Write a balanced...
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A digital watch battery draws 0.10 milliamperes of current, which is provided by a mercury battery whose net reaction is:
HgO(s) + Zn(s) → ZnO(s) + Hg(l)
If a partially used battery contains 1.40 g of each of these four substances, for how many hours will the watch continue to run?
hint:
Determine the limiting reagent in terms of moles. Then multiply by the stoichiometric ratio to determine the number of moles of electrons produced. Then convert moles of electons into Coulombs (Amps*seconds). Then you just need to divide by amps used to find the total number of seconds, and convert to hours. |
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