(a) Draw the Newman projection for each molecule shown here, looking down the C-C bond indicated by the arrow. (b) Which configuration do you think is more stable? Explain. H3C' *CH3 H3C 'CH3 cis-1,2-Dimethylcyclopropane trans-1,2-Dimethylcyclopropane
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- Consider the molecule 1-bromo-2-methylbutane. C3 and C4 should be drawn as Et as in theexample. This group is called an ethyl group and can be considered a sphere about twice the sizeof a methyl group. Draw the following Newman projections sighting down the C1C2 bond... a. The lowest potential energy conformation. b. The highest potential energy staggered conformation.translate the bond-line notation structure to the Newman projection by filling int the missing groups (A, B, C, D or E) on the lines in the Newman projection so they match the conformation given in the original structure. Circle if the conformation is a staggered or eclipsed......Draw the Newman pr0jecti0ns 0f the three p0ssible staggered c0nf0rmati0ns 0f2,3-dimethylbutane, viewed thr0ugh the C2—C3 b0nd. What are the relativeenergies of each c0nf0rmati0n?
- Given the compounds below, which is the more stable one based on their chair conformation?Is the 1st compound ( more, less or equally) stable than B? Pls show through illustrations of chair conformationsThen draw the most stable and least stable Newman projection conformation from the C4-C5 bond in the molecule above
- a. Draw the Newman projection for each molecule shown here, looking down the c-c bond indicated by the arrow. b. Which configuration do you think is more stable? Explain.In this molecule’s other chair conformation, how many (non H) axial positions are there?Build a model of methylcyclohexane, and use the model to complete the following Newmanprojections of methylcyclohexane in the chair conformation: a. When the methyl group is in an axial or equatorial (circle one) position, the molecule is inits lowest potential energy conformation. b. Label one Newman projection above anti and the other gauche to describe the relationshipbetween the methyl group and C3 of the ring. c. In general, which is a lower PE conformation, anti or gauche? d. Explain how your answer to b and c provide an explanation for why it is more favorable fora large group to be in an equatorial than an axial position.