A geneticist is trying to determine how many genes are found in a 300,000 bp region of DNA. Analysis shows that four H3K4me3-i.e., trimethylation of lysine 4 on the histone H3 protein - modifications are found in this piece of DNA. What might their presence suggest about the number of genes located there?
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- Homologous Recombination, Heteroduplex DNA, and Mismatch Repair Homologous recombination in E. coli leads to the formation of regions of heteroduplex DNA. By definition, such regions contain mismatched bases. Why doesn’t the mismatch repair system of E. coli eliminate these mismatches?A temperature-sensitive mutation is one in which the defect is not presented functionally until the temperature is raised. In the case described below, the enzymes function normally in bacteria at 37 °C, but are non-functional at 40 °C. Predict the detailed molecular consequences of a loss of function in a temperature-sensitive mutant for each of the following enzymes: a) DNA gyrase, b) DNA polymerase III, c) DNA ligase, d) DNA polymerase I.A recent estimate of the rate of base substitutions atSNP loci is about 1 × 10−8 per nucleotide pair pergamete.a. Based on this estimate, about how many de novomutations (that is, mutations not found in the genomes of your parents) are present in your own genome?b. Where and when did these de novo mutations inyour genome most likely occur?c. It has been calculated that each sperm made in a25-year-old man is the result on average of about300 rounds of cell division, starting with the firstmitotic division of the male zygote. In contrast,each mature oocyte found in a 5-month-old femalehuman fetus is the result of about 25 rounds of division, starting with the first mitotic division of thefemale zygote. What bearing do these calculations have on the estimate of the rate of base substitutions in humans, and on your answer to part (b)?
- Contrast the various types of DNA repair mechanisms known to counteract the effects of UV radiation. What is the role of visible light in repairing UV-induced mutations?Which of these two changes is more difficult for DNA repair enzymes to fix correctly? Explain why.Explain why the absorption of UV light by double-stranded DNA increases (the hyperchromic effect) when the DNA is denatured.
- A recent estimate of the rate of base substitutions atSNP loci is about 1 × 10−8 per nucleotide pair pergamete.a. Based on this estimate, about how many de novomutations (that is, mutations not found in the genomes of your parents) are present in your own genome?b. Where and when did these de novo mutations inyour genome most likely occur?Richard Boyce and Paul Howard-Flanders conducted an experimentthat provided biochemical evidence that thymine dimers areremoved from DNA by a DNA repair system. In their studies, bacterialDNA was radiolabeled so the amount of radioactivity reflectedthe amount of thymine dimers. The DNA was thensubjected to UV light, causing the formation of thymine dimers. When radioactivity was found in the soluble fraction, thymine dimershad been excised from the DNA by a DNA repair system.But when the radioactivity was in the insoluble fraction, the thyminedimers had been retained within the DNA. The following tableillustrates some of the experimental results involving a normalstrain of E. coli and a mutant strain that was very sensitive to killingby UV light: Explain the results found in this table. Why is the mutant strainsensitive to UV light?In some organisms, UV-induced thymine dimers can be repaired by photoreactivation, in which energy from visible light is used to split the bonds forming the cyclobutane ring ? true or false Non-homologous end joining occurs when enzymes cut out a few nucleotides around a double strand DNA break, and then fuse the ends back together (right) true or false?
- Briefly explain how or why making a region of DNA heterochromatic results in little or no expression of genes encoded in that region of the DNA.18A. How many equivalents of ATP are required to replicate a 1000 bp stretch of DNA? B. If the incorrect nt is incorporated how many equivalents of ATP are required to fix this?Much of DNA methylation in eukaryotes occurs at CpG dinucleotides, but some individual cytosine nucleotides are also methylated to form 5methylcytosine. Considering what you know about the process by which DNA methylation at CpG dinucleotides is maintained across cell division, do you think that methylation at individual C nucleotides would also be maintained by the same process? Explain your reasoning.