A given FM transmitter is modulated with a single sinusoid, the output for no load power is 100W into50Ω resistive load. Then, the frequency of the modulating signal is carefully adjusted from zero untilthe modulated carrier encountered its zero amplitude as observed in spectrum analyzer. Under theseconditions, determine the: (Use the provided Bessel table)a. the modulation index and the number of significant sideband.b. total power on its significant sidebands. c. relative total power of the carrier and each of sideband.Ans. (a) Mf =2.4, N=5; (b) 99.86 W; b Pc=0W, P1=27.04W, P2=18.49W, P3=4W, ModulationIndexCarrierSide Frequency Pairs16J101213 140.001.000.250.980.120.240.440.560.50.940.031.00.770.510.110.230.020.060.131.5012.00.220.80.350.032.40.520.430.200.060.022.5-0.050.500.450.220.070.020.013.0-0.260.340.490.310.130.040.014.0-0.40-0.070.360.430.280.130.050.025.0-0.18-0.33-0.340.050.360.390.260.130.050.025.45-0.120.260.010.400.360.320.190.090.036.00.15-0.28-0.240.110.360.250.130.060.027.0800.300.00-0.30-0.170.160.350.340.230.320.130.060.020.170.23-0.11-0.29-0.100.190.340.220.130.060.030.27-0230.030.260.208.650.06-0.240.340.28 0.180.100.050.029.0-0.090.250.140.31-0.180.06-0.27-0.22-0.06-0.230.330.210.120.060.030.0110.0-0.250.050.25-0.010.220.320.290.210.120.060.030.0112

Answered: A given FM transmitter is modulated…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

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A given FM transmitter is modulated with a single sinusoid, the output for no load power is 100W into
50Ω resistive load. Then, the frequency of the modulating signal is carefully adjusted from zero until
the modulated carrier encountered its zero amplitude as observed in spectrum analyzer. Under these
conditions, determine the: (Use the provided Bessel table)
a. the modulation index and the number of significant sideband.

b. total power on its significant sidebands.

c. relative total power of the carrier and each of sideband.

Ans. (a) Mf =2.4, N=5; (b) 99.86 W; b Pc=0W, P1=27.04W, P2=18.49W, P3=4W,

Modulation
Index
Carrier
Side Frequency Pairs
16
J10
12
13 14
0.00
1.00
0.25
0.98
0.12
0.24
0.44
0.56
0.5
0.94
0.03
1.0
0.77
0.51
0.11
0.23
0.02
0.06
0.13
1.5
01
2.0
0.22
0.8
0.35
0.03
2.4
0.52
0.43
0.20
0.06
0.02
2.5
-0.05
0.50
0.45
0.22
0.07
0.02
0.01
3.0
-0.26
0.34
0.49
0.31
0.13
0.04
0.01
4.0
-0.40
-0.07
0.36
0.43
0.28
0.13
0.05
0.02
5.0
-0.18
-0.33
-0.34
0.05
0.36
0.39
0.26
0.13
0.05
0.02
5.45
-0.12
0.26
0.01
0.40
0.36
0.32
0.19
0.09
0.03
6.0
0.15
-0.28
-0.24
0.11
0.36
0.25
0.13
0.06
0.02
7.0
80
0.30
0.00
-0.30
-0.17
0.16
0.35
0.34
0.23
0.32
0.13
0.06
0.02
0.17
0.23
-0.11
-0.29
-0.10
0.19
0.34
0.22
0.13
0.06
0.03
0.27
-023
0.03
0.26
0.20
8.65
0.06
-0.24
0.34
0.28 0.18
0.10
0.05
0.02
9.0
-0.09
0.25
0.14
0.31
-0.18
0.06
-0.27
-0.22
-0.06
-0.23
0.33
0.21
0.12
0.06
0.03
0.01
10.0
-0.25
0.05
0.25
-0.01
0.22
0.32
0.29
0.21
0.12
0.06
0.03
0.01
12

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