A Gold (Au) has a face-centered cubic structure with a unit cell edge length of 407.8 pm. What is the calculated value of the density of gold based on this information? 1 pm =1 x 10 -10 Avogadro's number = 6.022 x 1023 Molar mass of gold = 197 g/mol cm. Selected Answer: O d. 4.82 g/cm3 Answers: O a. 19.28 g/cm3 b. 11.6 g/cm3 c. 15.78 g/cm d. 4.82 g/cm3

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Q: If a body-centered cubic unit cell has a volume of 1.447 x 10° pm, what must be the dimension of the…

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Q: 2 Bedy-Centered Unit Cell (a) (b) Fig 5. Body-Centered Cubic (BCC) Unit Cell. (a) Ball-and-Stick…

A: Z--> no. Of atom present in the unit cell. a= edge length of cube  r= radius of an atom.

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A: Given:Volume = 4.32×10-23 cm3

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Q: Calcium crystallizes in a face-centered cubic structure. The edge length of its unit cell is 558.8…

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Q: Calcium crystallizes in a face-centered cubic lattice. The radius of calcium is 196 pm. What is the…

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Q: 2. Body-Centered Unit Cell (a) (b) Fig 5. Body-Centered Cubic (BCC) Unit Cell. (a) Ball-and-Stick…

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Q: An element crystallizes in a face-centered cubic lattice and has a density of 1.456 g/cm³. The edge…

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A: The expression for calculating the density of a solid crystal:

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Q: MgO has a face-centered cubic unit cell in which the O2- anions occupy corners and face centers,…

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Q: I'm not sure how to do this one.

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Q: calculate a value for Avogadro's Number.

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Q: An element crystallizes in a face-centered cubic lattice and has a density of 1.27 g/cm3. The edge…

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A: The density of fcc unit cell of nickel is calculated in step two.

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