1.Vanadium crystallizes in a body-centered cubic lattice, and the length of the edge of a unit cell is 305 pm. What is the density of V? The atomic mass of V is 50.94 amu. a.5.96 g cm-3 b.2.98 g cm-3 c.5.96 x 10-30 g cm-3 d.2.98 x 10-6 g cm-3

1.Vanadium crystallizes in a body-centered cubic lattice, and the length of the edge of a unit cell is 305 pm. What is the density of V? The atomic mass of V is 50.94 amu. a.5.96 g cm-3 b.2.98 g cm-3 c.5.96 x 10-30 g cm-3 d.2.98 x 10-6 g cm-3

Chemistry: Principles and Reactions

8th Edition

ISBN:9781305079373

Author:William L. Masterton, Cecile N. Hurley

Publisher:William L. Masterton, Cecile N. Hurley

Chapter1: Matter And Measurements

Section: Chapter Questions

Problem 16QAP: Computers are not supposed to be in very warm rooms. The highest temperature tolerated for maximum...

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Concept explainers

Crystal Lattices and Unit Cell

Consider a crystal. The regular and repeating pattern of constituent particles is the most distinguishing feature of crystalline solids. A crystal lattice is formed when these particles are replaced with representative points. The three-dimensional arrangement of constituent particles is known as a crystal lattice. Unit cell is that the smallest portion of a space lattice which when repeated in several directions, generate the whole lattice. Unit cell is a building block of a lattice. It is the smallest unit of cell.

Question

1.Vanadium crystallizes in a body-centered cubic lattice, and the length of the edge of a unit cell is 305 pm. What is the density of V? The atomic mass of V is 50.94 amu.

a.5.96 g cm^-3

b.2.98 g cm^-3

c.5.96 x 10^-30 g cm^-3

d.2.98 x 10^-6 g cm^-32.Given the following data, calculate the lattice energy of aluminum oxide, Al₂O₃.

a.-13 272 kJ mol^-1b.-8300 kJ mol^-1c.-15 333 kJ mol^-1d. -10 610 kJ mol^-1

IEA = 577.5 kJ mol1
IE = 1817 kJ mol1
IEX = 2745 kJ mol1
AHSub(Al) = 330 kJ mol1
EA = 141 kJ mol1
EA3 = -798 kJ mol1
BDE (O = O) = 498 kJ mol
AH(Al,O3) = -1675.7 kJ mol1
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