A kindergarten class has four left-handed children and twelve right-handed children. Two children are selected without replacement for a shoe-tying lesson. Let X = the number who are left-handed. (a) The simple events in the sample space are (RR, RL, LR, LL}. For instance, one simple event is RL, indicating that the first child is right-handed and the second one is left-handed. Find the probabi for each of the simple events in the sample space. (Hint: A tree diagram may help you solve this.) P(RR) = P(RL) = P(LR) = P(LL) = (b) Find the probability distribution function for X. 1 P(X = k)
A kindergarten class has four left-handed children and twelve right-handed children. Two children are selected without replacement for a shoe-tying lesson. Let X = the number who are left-handed. (a) The simple events in the sample space are (RR, RL, LR, LL}. For instance, one simple event is RL, indicating that the first child is right-handed and the second one is left-handed. Find the probabi for each of the simple events in the sample space. (Hint: A tree diagram may help you solve this.) P(RR) = P(RL) = P(LR) = P(LL) = (b) Find the probability distribution function for X. 1 P(X = k)
Chapter8: Sequences, Series,and Probability
Section8.7: Probability
Problem 4ECP: Show that the probability of drawing a club at random from a standard deck of 52 playing cards is...
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A kindergarten class has four left-handed children and twelve right-handed children. Two children are selected without replacement for a shoe-tying lesson. Let X = the number who are left-handed.
(a) The simple events in the sample space are {RR, RL, LR, LL}. For instance, one simple event is RL, indicating that the first child is right-handed and the second one is left-handed. Find the probability for each of the simple events in the sample space. (Hint: A tree diagram may help you solve this.)
(b) Find the probability distribution function for X.
Transcribed Image Text:A kindergarten class has four left-handed children and twelve right-handed children. Two children are selected without replacement for a shoe-tying lesson. Let X = the number who are left-handed.
(a) The simple events in the sample space are {RR, RL, LR, LL}. For instance, one simple event is RL, indicating that the first child is right-handed and the second one is left-handed. Find the probability
for each of the simple events in the sample space. (Hint: A tree diagram may help you solve this.)
P(RR)=
%3D
P(RL) =
P(LR) =
P(LL) =
(b) Find the probability distribution function for X.
k
1
P(X = k)
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