A large slab of steel at a uniform tempering temperature of 200°C and suddenly quenching, and it surface temperature lowered to 70°C. calculate the required time when the temperature at a depth 4.0 cm has dropped to 120°C? Given: steel [k =45 W/m°C, a=1.4×10³ m²/s, c=0.46 kJ/kg]

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)
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ISBN:9781305387102
Author:Kreith, Frank; Manglik, Raj M.
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Chapter6: Forced Convection Over Exterior Surfaces
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A large slab of steel at a uniform tempering temperature of 200°C and suddenly
quenching, and it surface temperature lowered to 70°C. calculate the required time when
the temperature at a depth 4.0 cm has dropped to 120°C?
Given: steel [k =45 W/m°C, a=1.4×10-5 m²/s, c=0.46 kJ/kg]
Transcribed Image Text:A large slab of steel at a uniform tempering temperature of 200°C and suddenly quenching, and it surface temperature lowered to 70°C. calculate the required time when the temperature at a depth 4.0 cm has dropped to 120°C? Given: steel [k =45 W/m°C, a=1.4×10-5 m²/s, c=0.46 kJ/kg]
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