A local health centre noted that in a sample of 400 patients, 80 were referred to them by the loca hospital. a. Provide a 95% confidence interval for all the patients who are referred to the health centre by the hospital.

Q: A June 2020 Angus Reid poll of 1510 Canadian adults found that 53% support the idea of a 30 hour…

A: Given Data: p^=0.53n=1510   z-value corresponding to 95% Confidence level=1.96

Q: 12. In a sample of 600 Canadians, 265 say they would rather retire in the US than in Canada.…

A:

Q: A computer software magazine compares the rates of malware infection for computers protected by…

A: There are two independent samples which are software A and software B. Both samples are drawn from…

Q: According to a Harris Interactive survey of 2401 adults conducted in April 2009, 25% of adults do…

A:

Q: In a random sample of 145 UNO students, we find that 53% have attended a Maverick hockey game at…

A:

Q: 5.From a sample of 1,000 college students, 28% watch the Super Bowl game each year. Find the margin…

A:

Q: From a survey of 400 new Wawasan Open University students chosen at random, it was discovered that…

A:

Q: Of 118 randomly selected adults, 34 were found to have high blood pressure. Construct a 95%…

A: According to the given information, we have Total number of adults = 118 34 were found to have high…

Q: In a study of 480 households, 168 households were found to have 4 cell phones. Find a 95% confidence…

A: Given: x=168 n=480 p^=xn=168480=0.35

Q: An environmental science teacher at a high school with a large population of students wanted to…

A: The 95% confidence interval for the proportion of all students at the school who would respond yes…

Q: In a study of 200 accidents that required treatment in an emergency room, 80 occurred at work. Find…

A: Obtain the 90% confidence interval for the true proportion of accidents that occurred at work. The…

Q: In a survey of 1,200 social media users, 56% said it is not okay to be friends with your boss.…

A:

Q: Of 380 randomly selected medical students, 21 said that they planned to work in a rural community.…

A: Sample proportion=p^=21380z=critical value for 95% confidence interval=1.96n=sample size=380

Q: In a Gallup Poll of 1005 individuals, 452 thought they were better off financially than a year ago.…

A: Given; p=452n=1005 95% confidence interval is given by- p^±z×p^(1-p^)n true proportion is given as-…

Q: In a recent poll, 560 people were asked if they liked dogs, and 22% said they did. Find the margin…

A: For 95% confidence intervalα=1-CI=1-0.95=0.05So, zα2=z0.052=z0.025=1.96

Q: A survey found that out of 900 workers, 150 said they were interrupted by frank phone calls. Find…

A:

Q: In a survey of 50,00 people, 80% indicated that they listened to their favorite radio station…

A: Hern= 5000 P^ = 0.80 We have to construct 95% ci for p

Q: Of 380 randomly selected medical students, 21 said that they planned to work in a rural community…

A: Given that, Out Of 380 randomly selected medical students, 21 said that they planned to work in a…

Q: In a recent poll, 150 people were asked if they liked dogs, and 55% said they did. Find the margin…

A:

Q: The figure to the right shows the results of a survey in which 1005 adults from Country​ A, 1023…

A: From the provided information, Sample size of Country B (n) = 1023 Sample proportion (p̂) = 0.22…

Q: In a survey of 7100 t.v views, 40% said they watch network news programs. Find the margin of error…

A: Solution: From the given information, p-hat=0.40 and n=7100. The confidence level is 0.95.

Q: In a recent poll, 240 people were asked if they liked dogs, and 32% said they did. Find the margin…

A: Find z-critical value:…

Q: 4. A market-research firm asked 300 people about their shampoo-purchasing habits. Fifty-five people…

A:

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the​ poll,…

A: Given , n = 1008 x = 598

Q: Using the accompanying colleges and universities data to find 95% confidence intervals for the…

A: Given:   Liberal Arts Colleges Research Universities 1169 1117 1194 1133 1204 1148 1210…

Q: In a recent poll, 260 people were asked if they liked dogs, and 67% said they did. Find the margin…

A: Given: p = 67%=0.67 n= 260 The value of z at a 90% confidence level is 1.645, which can be found by…

Q: 6) An Internet service provider sampled 590 customers and found that 85 of them experienced an…

A: According to the given information, we have Total number of customers = 590 85 of them experienced…

Q: In a sports poll, 142 of 500 randomly selected Americans indicated that they consider themselves to…

A: Given that, In a sports poll, 142 of 500 randomly selected Americans indicated that they consider…

Q: Of 380 randomly selected medical students, 21 said that they planned to work in a rural community.…

A: Note- Here I am taking the sample size as 380 because then only the answer will match with the given…

Q: Of 254 randomly selected medical students, 25 said that they planned to work in a rural community.…

A: It is given that, the number of students said that they planned to work in natural community   (x)…

Q: In a sample of 600 Ottawa families, it is found that 360 rent their dwellings while 240 own their…

A: It is given that sample size (n) is 360 and x is 240.

Q: In a random sample of 184 college students, 97 had part-time jobs. Find the margin of error for the…

A: Given : Sample Size, n = 184 Number of successes, x = 97 confidence level,c=0.99

Q: In a sample of 900 people, 378 say they snooze the alarm more than once in the morning. Find a 95%…

A: Given,   The sample proportion is,

Q: 1. In a poll of 2,500 likely voters, 966 say that the Philippines spend too little on education.…

A:

Q: An environmental science teacher at a high school with a large population of students wanted to…

A: Question : (b) Given the method used by the environmental science teacher to collect the responses,…

Q: d) Provide the appropriate interpretation for the confidence interval.

A:

Q: The figure to the right shows the results of a survey in which 1005 adults from Country​ A, 1023…

A: For the given data Construct a 99​% confidence interval for the population proportion of adults s…

Q: Exercise 3 An employment counselor found that in a sample of 100 unemployed workers, 65% were not…

A: Given that : 1) sample size = 49  Mean = $ 23.45 S. D = $ 2.80 90% confidence interval.

Q: A survey​ asks, "If the husband in a family wants​ children, but the wife decides that she does not…

A: We have to create 99% confidence interval for the population proportion.

Q: In a survey of 32 students at a local high school, 17 support changing the schools mascot. Find the…

A:

Q: in a recent survey of 1000 adults ages 18 to 40, 34% said they had no credit cards. find the 95%…

A: The sample size n=1000. The sample proportion is 0.34. The confidence level is 95%. The area between…

Q: In a recent poll, 110 people were asked if they liked dogs, and 40% said they did. Find the margin…

A: For 99% confidence intervalα=1-CI=1-0.99=0.01So, zα2=z0.012=z0.005=2.576

Q: b. Construct a 90% confidence interval for the percentage of all judges who are in favor of the…

A: a. A random sample of 15 judges and asked them whether or not they favor the death penalty in which…

Q: 2. Estimate the proportion of WCU students who have type B blood using 95% confidence interval.…

A: Given , n=100x=24p^=xn=24100=0.241-p^=1-0.24=0.76α=1-0.95=0.05α2=0.025Z0.025=1.96

Q: A recent survey of 1,000 people found that 90% of Americans support background checks for purchasing…

A:

Q: An airline transports over 10 000 passengers daily, and the airline is curious what proportion of…

A: Critical value: Using Excel formula "=NORM.S.INV(1-(0.1/2))", the z-value is obtained as 1.645.

Q: A survey found that out of 800 workers, 150 said they were interrupted by frank phone calls. Find…

A: Given,n=800x=150p^=xnp^=150800=0.18751-p^=1-0.1875=0.8125α=1-0.95=0.05α2=0.025Z0.025=1.96

Q: Of 380 randomly selected medical students, 21 said that they planned to work in a rural community.…

A: Here we need to construct a 95% confidence interval for the population proportion. Here the sample…