A manufacturing company produces four parts that require the use of a lathe and a drill press. The two machines operate 10 hours a day each. The following table provides the time in minutes required by each part: Production time in min Product Lathe Drill press 3 6 3. 4 4. 7. 254

Practical Management Science
6th Edition
ISBN:9781337406659
Author:WINSTON, Wayne L.
Publisher:WINSTON, Wayne L.
Chapter8: Evolutionary Solver: An Alternative Optimization Procedure
Section: Chapter Questions
Problem 36P
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A manufacturing company produces four
parts that require the use of a lathe and a drill
press. The two machines operate 10 hours a
day each. The following table provides the
time in minutes required by each part:
Product
Production time in min
Drill press
Lathe
1
3
4
4
7
Additionally, the number of units of part 1
may not exceed that of part 2.
Assuming that
x; : number of units need to be produced from product i, wherei e (1,2,3,4)
The constraints and the objectives that are used to "reduce the amount of overtime for both
machines per day", are:
O a. Minimize s, +s +s, + s,
51+6x2+ 4rz +7x4 + s, - s
3x1 + 2r2 + 5rz + 4x4 + s, – s=600
• b. Minimize i-1 $i
= 600
5x1+6x2 +4rz + 7x4 + s,
S = 600
3x1 + 2x2 +5x3 + 4x4 + s,
600
O c. Minimize s, + s
521 +622 +4r3 + 7x4 + s,-s = 10
O d. Minimize s, + s,
3x1+2x2 +5x3 + 4x4 + s, – 8, = 600
O e. Minimize-1 $
521 + 6x2 +4x3 + 7x4 + 8,s
600
3x1 + 2r2 + 5x3 +4x4 + 8,
600
3254
Transcribed Image Text:A manufacturing company produces four parts that require the use of a lathe and a drill press. The two machines operate 10 hours a day each. The following table provides the time in minutes required by each part: Product Production time in min Drill press Lathe 1 3 4 4 7 Additionally, the number of units of part 1 may not exceed that of part 2. Assuming that x; : number of units need to be produced from product i, wherei e (1,2,3,4) The constraints and the objectives that are used to "reduce the amount of overtime for both machines per day", are: O a. Minimize s, +s +s, + s, 51+6x2+ 4rz +7x4 + s, - s 3x1 + 2r2 + 5rz + 4x4 + s, – s=600 • b. Minimize i-1 $i = 600 5x1+6x2 +4rz + 7x4 + s, S = 600 3x1 + 2x2 +5x3 + 4x4 + s, 600 O c. Minimize s, + s 521 +622 +4r3 + 7x4 + s,-s = 10 O d. Minimize s, + s, 3x1+2x2 +5x3 + 4x4 + s, – 8, = 600 O e. Minimize-1 $ 521 + 6x2 +4x3 + 7x4 + 8,s 600 3x1 + 2r2 + 5x3 +4x4 + 8, 600 3254
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