A mild steel specimen of Diameter 9 mm,Length 11 cm is subjected to tensile load andit is found that the Strain-induced on thespecimen is 18 x 10-3. Take the Modulus ofelasticity as 201 x 103 MPa.Determine the followingi) Tensile Loadii) Tensile Stressiii) Change in Lengthiv) Final cross-sectional area at failure if thepercentage of reduction in area is 49 %.

Answered: Image /qna-images/answer/82f732fd-9c50-474f-8b68-bdf6b03734f6.jpg

A mild steel specimen of Diameter 9 mm, Length 11 cm is subjected to tensile load and it is found that the Strain-induced on the specimen is 18 x 10-3. Take the Modulus of elasticity as 201 x 10³ MPa. Determine the following i) Tensile Load ii) Tensile Stress iii) Change in Length ) Finel onol oro at feilu re if t be

A mild steel specimen of Diameter 9 mm, Length 11 cm is subjected to tensile load and it is found that the Strain-induced on the specimen is 18 x 10-3. Take the Modulus of elasticity as 201 x 10³ MPa. Determine the following i) Tensile Load ii) Tensile Stress iii) Change in Length ) Finel onol oro at feilu re if t be

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

The following data are obtained from a tensile test of a copper specimen. - The load at the yield point is 150 kN. - Length of the specimen is 24 mm. - The yield strength is 78 kN/mm2. - The percentage of elongation is 42 %. Determine the following iii) Stress under an elastic load of 14 kN, iv) Young's Modulus if the elongation is 1.7 mm at 14 kN and (v) Final diameter if the percentage of reduction in area is 26 %. I wont answer for this three questions only: 1)Final Area of the Specimen at Fracture (in mm) 2)Final Diameter of the Specimen after Fracture (in mm) 3)Initial Cross-sectional Area (in mm2)
Strain energy is the A. energy stored in a body when strained within elastic limits B. energy stored in a body when strained upto the breaking of a specimen C. maximum strain energy which can be stored in a body D. proof resilience per unit volume of a material
A cylindrical specimen of aluminum having a diameter of 19 mm (0.75 in.) and length of 200 mm(8.0 in.) is deformed elastically in tension with a force of 48,800 N (11,000 lbf). Using the data inTable 6.1, determine the following:(a) The amount by which this specimen will elongate in the direction of the applied stress.(b) The change in diameter of the specimen. Will the diameter increase or decrease? (Complete Answer, Thank you)
Two round rods, one of steel, the other of brass, are joined end to end. Each rod is 0.5 m long and 2 cm in diameter. The combination is subjected to a tensile force of 5000 N. Find the strain in each rod. Young's Modulus of Steel use 20×10¹⁰ Pa, of brass use 10×10¹⁰ Pa. Find the elongation of each rod.
A mild steel specimen of Diameter 9 mm, Length 11 cm is subjected to tensile load and it is found that the Strain-induced on the specimen is 18 x 10-3. Take the Modulus of elasticity as 201 x 103 MPa. Determine the following i) Cross-sectional Area, (in mm2) ii) Tensile Load iii) Tensile Stress iv) Change in Length iiv) Final cross-sectional area at failure if the percentage of reduction in area is 49 %.
Draw the tensile curves of the following materials, taking into account the appropriate elongation at break, modulus of elasticity and tensile stress, on the side stress-strain graph. a)Low carbon steel (Ecelik=200Gpa),(Syield=300MPa),(Stensile=400MPa) b)High carbon steel (Esteel=200GPa),(Stensile=700MPa) c)Aluminum (Ealuminum=70GPa), (Syield=200MPa),(Stensile=300MPa) d)Cast iron (Ecast iron=120GPa),(Stensile=200MPa)
Choose the correct answer Stress divided by Rate of strain is: d. Velocity a. Surface tension f. Kinematic viscosity b. Density e. Dynamic Viscosity c. Unit less
Let's consider a rod having a solid circular cross-section with diameter of 5 mm and it is made of a material having a Young's modulus E = 120 Gpa anda Poisson's ratio of 0.33. If a tensile force F is subjected to that rod cross-section, the diameter becomes 4.995 mm. determine the applied force F.
Pls answer thank you! A circular rod is 128 mm in diameter and carries gauge marks placed 50.8 mm apart. When the rod is subjected to an axial force of 31,150 N, the distance between the gauge marks is 50.86 mm. What is the modulus of elasticity of this material?
Consider the modulus of elasticity of aluminum to be 10,000 lb / in2.Verify homogeneity in the units. An aluminum block of rectangular cross section is subjected to an axial compressive force, if the side measuring 1.5 in changes in length to 1.500132 in, determine the poisson's ratio and the new length of the side measuring 5 cm.
The stress-strain diagram of a reinforcement steel having a cross-sectional diameter of 12 mmdiameter and 100 mm gage length is determined after its tensile strength test as follows. Based on the stressstrain diagram determine the followings properties of the material (Poisson’s ratio of the material is 0.32) : a) Modulus of elasticityb) Yield strengthc) Toughnessd) Resiliencee) Shear modulusf) Bulk modulusg) Ductility as described bypercent change in length
Can anyone explain why there are two strains calculated here (Engineering and true)