A mixture hot gases expands, changing volume from 2.45 L to 6.82 L, against a constant pressure of 3.22 atm. The P–V work involved is

Chemistry: Principles and Practice
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ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter17: Chemcial Thermodynamics
Section: Chapter Questions
Problem 17.6QE
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A mixture hot gases expands, changing volume from 2.45 L to 6.82 L, against a constant pressure of 3.22 atm.

The P–V work involved is

Expert Solution
Step 1

The initial volume = 2.45 L

The final volume = 6.82 L

Volume difference, ΔV = (final -Initial) volume=(6.82-2.45) L=4.37 L

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