Question
Asked Oct 11, 2019
A mixture of 56.0 g of S and 1.10×102 g of Cl2 reacts completely to form S2Cl2 and SCl2.
 
 

Part A

Find the mass of S2Cl2 formed
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Expert Answer

Step 1

Balanced equation for the given reaction is shown below. Number of moles of reactants is calculated.

Balanced equation: 3 S 2 Cl
S2CI,SCI
Mass
No. of moles of S
Molar mass
56.0 g
= 1.75 mol
11
32.07 g/mol
1.10x102 g
70.91 g/mol
No. of moles of Cl
1.55 mol
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Balanced equation: 3 S 2 Cl S2CI,SCI Mass No. of moles of S Molar mass 56.0 g = 1.75 mol 11 32.07 g/mol 1.10x102 g 70.91 g/mol No. of moles of Cl 1.55 mol

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Step 2

Determine limitin...

2 mol Cl, reacts to give 1 mol S,Cl,
3 mol S reacts to give 1 mol S,Cl
No. of moles of s,Cl, formed when 1.55 mol Cl, is reacted
1 mol S2Cl2
2 mol Cl
=1.55 mol Cl, x
0.775 mol S2CI
No. of moles of Cl, needed to react with 1.75 mol S is,
1 mol S2CI
1.75 mol Sx
3 mol S
=0.583 mol S2CI
Limiting reagent > S
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2 mol Cl, reacts to give 1 mol S,Cl, 3 mol S reacts to give 1 mol S,Cl No. of moles of s,Cl, formed when 1.55 mol Cl, is reacted 1 mol S2Cl2 2 mol Cl =1.55 mol Cl, x 0.775 mol S2CI No. of moles of Cl, needed to react with 1.75 mol S is, 1 mol S2CI 1.75 mol Sx 3 mol S =0.583 mol S2CI Limiting reagent > S

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