A movie stuntman (mass 80.0 kg) stands on a window ledge 6. Conservation of Momentum (Collision) & Mech. Energy. 5.0 m above the floor. Grabbing a rope attached to a chandelier, he swings down to grapple with the movie's villain (mass 70.0 kg), who is standing directly under the chandelier. (Assume that the stuntman's center of mass moves downward 5.0 m. He releases the rope just as he reaches the villain.) (a) With what speed do the entwined foes start to slide across the floor? (b) If the coefficient of kinetic friction of their bodies with the floor is Hk = 0.250, how far do they slide? 5,0 m m = 80.0 kg 70.0 kg m =

Inquiry into Physics
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ISBN:9781337515863
Author:Ostdiek
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Chapter3: Energy And Conservation Laws
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Problem 6P: A basketball with a mass of 0.62 kg falls vertically to the floor where it hits with a speed of 6...
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A movie stuntman (mass 80.0 kg) stands on a window ledge
6. Conservation of Momentum (Collision) & Mech. Energy.
5.0 m above the floor. Grabbing a rope attached to a chandelier, he swings down to grapple with the movie's villain (mass
70.0 kg), who is standing directly under the chandelier. (Assume that the stuntman's center of mass moves downward 5.0
m. He releases the rope just as he reaches the villain.)
(a) With what speed do the entwined foes start to slide across the floor?
(b) If the coefficient of kinetic friction of their bodies with the floor is Hk = 0.250, how far do they slide?
5,0 m
m = 80.0 kg
70.0 kg
m =
Transcribed Image Text:A movie stuntman (mass 80.0 kg) stands on a window ledge 6. Conservation of Momentum (Collision) & Mech. Energy. 5.0 m above the floor. Grabbing a rope attached to a chandelier, he swings down to grapple with the movie's villain (mass 70.0 kg), who is standing directly under the chandelier. (Assume that the stuntman's center of mass moves downward 5.0 m. He releases the rope just as he reaches the villain.) (a) With what speed do the entwined foes start to slide across the floor? (b) If the coefficient of kinetic friction of their bodies with the floor is Hk = 0.250, how far do they slide? 5,0 m m = 80.0 kg 70.0 kg m =
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