A new golf ball has been designed to improve driving distance off the tee when compared to their market competitor. To test their new ball, nine golfers hit a drive with the current ball and then hit another drive with the new ball. The distance in yards for each golfer is shown in the following table. Current Golf Ball New Golf Ball (Population 1) (Population 2) 212 215 236 228 250 256 243 264 250 248 235 255 230 239 225 218 220 239 а). Use = 0.05. State the null and alternative hypothesis. b). Use a = 0.05. State the decision rule in terms of the critical value. с). Use a = 0.05. What is your conclusion?

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.6: Summarizing Categorical Data
Problem 25PPS
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A new golf ball has been designed to improve driving distance off the tee when compared to their market
competitor. To test their new ball, nine golfers hit a drive with the current ball and then hit another drive
with the new ball. The distance in yards for each golfer is shown in the following table.
Current Golf Ball
New Golf Ball
(Population 1)
(Population 2)
212
215
236
228
250
256
243
264
250
248
235
255
230
239
225
218
220
239
а).
Use
= 0.05. State the null and alternative hypothesis.
b).
Use g = 0.05. State the decision rule in terms of the critical value.
с).
Use
= 0.05. What is your conclusion?
d).
Determine the 95% confidence interval in mean difference for distance in yards between current
golf ball and new golf ball. Briefly explain what the 95% interval estimate tells you about the new
golf ball.
Transcribed Image Text:A new golf ball has been designed to improve driving distance off the tee when compared to their market competitor. To test their new ball, nine golfers hit a drive with the current ball and then hit another drive with the new ball. The distance in yards for each golfer is shown in the following table. Current Golf Ball New Golf Ball (Population 1) (Population 2) 212 215 236 228 250 256 243 264 250 248 235 255 230 239 225 218 220 239 а). Use = 0.05. State the null and alternative hypothesis. b). Use g = 0.05. State the decision rule in terms of the critical value. с). Use = 0.05. What is your conclusion? d). Determine the 95% confidence interval in mean difference for distance in yards between current golf ball and new golf ball. Briefly explain what the 95% interval estimate tells you about the new golf ball.
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