A pendulum consists of a bob of mass m=0.233 kgm=0.233 kgand a massless inextensible string of length L=1.20 mL=1.20 m. It is suspended from a fixed point at height H=0.623 mH=0.623 mabove a horizontal floor with a coefficient of friction u=0.175µ=0.175. Initially, the bob of the pendulum is lying on the floor at rest vertically below the point of suspension. A horizontal impulse P=2.02 kg.ms-1P=2.02 kg.ms-lis imparted to the bob at some instant, such that it acquires a velocity v=Pmv=mP. After the bob slides for some distance, the string becomes taut and the bob lifts off the floor. Calculate the angle at which the string becomes taut. At what time does the bob leave the surface; i.e., the string become taut? What is the kinetic energy of the bob just after the lift-off?

Physics for Scientists and Engineers: Foundations and Connections
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Chapter16: Oscillations
Section: Chapter Questions
Problem 75PQ: A spherical bob of mass m and radius R is suspended from a fixed point by a rigid rod of negligible...
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A pendulum consists of a bob of mass
m=0.233 kgm=0.233 kgand a massless
inextensible string of length L=1.20
mL=1.20 m. It is suspended from a fixed
point at height H=0.623 mH=0.623 mabove
a horizontal floor with a coefficient of
friction u=0.175µ=0.175. Initially, the bob of
the pendulum is lying on the floor at rest
vertically below the point of suspension. A
horizontal impulse P=2.02 kg.ms-1P=2.02
kg.ms-lis imparted to the bob at some
instant, such that it acquires a velocity
v=Pmv=mP. After the bob slides for some
distance, the string becomes taut and the
bob lifts off the floor.
Calculate the angle at which the string
becomes taut.
At what time does the bob leave the
surface; i.e., the string become taut?
What is the kinetic energy of the bob just
after the lift-off?
Transcribed Image Text:A pendulum consists of a bob of mass m=0.233 kgm=0.233 kgand a massless inextensible string of length L=1.20 mL=1.20 m. It is suspended from a fixed point at height H=0.623 mH=0.623 mabove a horizontal floor with a coefficient of friction u=0.175µ=0.175. Initially, the bob of the pendulum is lying on the floor at rest vertically below the point of suspension. A horizontal impulse P=2.02 kg.ms-1P=2.02 kg.ms-lis imparted to the bob at some instant, such that it acquires a velocity v=Pmv=mP. After the bob slides for some distance, the string becomes taut and the bob lifts off the floor. Calculate the angle at which the string becomes taut. At what time does the bob leave the surface; i.e., the string become taut? What is the kinetic energy of the bob just after the lift-off?
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