A pendulum swings in simple harmonic motion at the surface of the Earth, the angle the pendulum makes relative to its equilibrium position is given by theta( = (0.140 rad) cos (5.72t) where t is in seconds. What is the length of this pendulum? * %3D O 0.140 m O 0.250 m O 0.300 m O 0.439 m O 0.801 m

Principles of Physics: A Calculus-Based Text
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ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
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Chapter12: Oscillatory Motion
Section: Chapter Questions
Problem 14P: In an engine, a piston oscillates with simple harmonic motion so that its position varies according...
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A pendulum swings in simple harmonic motion at the surface of the Earth, the
angle the pendulum makes relative to its equilibrium position is given by theta(
= (0.140 rad) cos (5.72t) where t is in seconds. What is the length of this
pendulum? *
%3D
O 0.140 m
O 0.250 m
O 0.300 m
O 0.439 m
O 0.801 m
Transcribed Image Text:A pendulum swings in simple harmonic motion at the surface of the Earth, the angle the pendulum makes relative to its equilibrium position is given by theta( = (0.140 rad) cos (5.72t) where t is in seconds. What is the length of this pendulum? * %3D O 0.140 m O 0.250 m O 0.300 m O 0.439 m O 0.801 m
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