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A piece of metal weighing 83.60 g was heated to 99.6°C and then put into 41.90 g of water (initially at 16.2°C ). The metal and water were allowed to come to the same temperature, determined to be 27.3°C . Assuming no heat lost to the environment, calculate the specific heat of the metal. (CH2O = 4.181 J/g°C) %3D Round your answer to 2 decimal places. Your Answer:

A piece of metal weighing 83.60 g was heated to 99.6°C and then put into 41.90 g of water (initially at 16.2°C ). The metal and water were allowed to come to the same temperature, determined to be 27.3°C . Assuming no heat lost to the environment, calculate the specific heat of the metal. (CH2O = 4.181 J/g°C) %3D Round your answer to 2 decimal places. Your Answer:

Chemistry by OpenStax (2015-05-04)
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter5: Thermochemistry
Section: Chapter Questions
Problem 12E: An aluminum kettle weighs 1.05 kg. (a) What is the heat capacity of the kettle? (b) How much heat is...
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A piece of metal weighing 83.60 g was heated to 99.6°C and then put into 41.90 g of water (initially at 16.2°C ). The metal and water were allowed to come to the same temperature, determined to be 27.3°C. Assuming no heat lost to the environment, calculate the specific heat of the metal. (CH2O = 4.181 J/g°C) %3D Round your answer to 2 decimal places. Your Answer: Answer units D Add attachments to support your work
Transcribed Image Text:A piece of metal weighing 83.60 g was heated to 99.6°C and then put into 41.90 g of water (initially at 16.2°C ). The metal and water were allowed to come to the same temperature, determined to be 27.3°C. Assuming no heat lost to the environment, calculate the specific heat of the metal. (CH2O = 4.181 J/g°C) %3D Round your answer to 2 decimal places. Your Answer: Answer units D Add attachments to support your work
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