Answered: A playground is on the flat roof of a…

Physics for Scientists and Engineers with Modern Physics

10th Edition

ISBN:9781337553292

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter4: Motion In Two Dimensions

Section: Chapter Questions

Problem 35AP

See similar textbooks

Related questions

Concept explainers

Question

100%

A playground is on the flat roof of a city school, h_b = 6.70 m above the street below (see figure). The vertical wall of the building is h = 7.90 m high, to form a 1.2-m-high railing around the playground. A ball has fallen to the street below, and a passerby returns it by launching it at an angle of ? = 53.0° above the horizontal at a point d = 24.0 m from the base of the building wall. The ball takes 2.20 s to reach a point vertically above the wall.

Question: (a) Find the speed at which the ball was launched.

A playground is on the flat roof of a city school, h, = 6.70 m above the street below (see figure). The vertical wall of the building is h = 7.90 m high, to form a 1.2-m-high railing around the playground. A ball has
fallen to the street below, and a passerby returns it by launching it at an angle of 0 = 53.0° above the horizontal at a point d = 24.0 m from the base of the building wall. The ball takes 2.20 s to reach a point
vertically above the wall.
A man onhe ground kicking a ball to children on a flat rooftois
epveen the man and the building is labeled d. The heighttothe le
building is labeled h. The motion of the ball is depiced as a parabota
originatng from the man on the grond and ending at the rooftod. The vector of
dis
the initlal motion of the ball makes an angle e with the horizontal
(a) Find the speed at which the ball was launched.
6.3
Your response differs from the correct answer by more than 10%. Double check your calculations. m/s

Expert Solution

Step 1

The speed at which the ball was launched =?

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions