A potential difference V is applied to a wire of cross-sectional area A, length L, and resistivity r.You want to change the applied potential difference and stretch the wire so that the energy dissipation rate is multiplied by 30.0 and the current is multiplied by 4.00. Assuming the wire’s density does not change, what are (a) the ratio of the new length to L and (b) the ratio of the new cross-sectional area to A?
A potential difference V is applied to a wire of cross-sectional area A, length L, and resistivity r.You want to change the applied potential difference and stretch the wire so that the energy dissipation rate is multiplied by 30.0 and the current is multiplied by 4.00. Assuming the wire’s density does not change, what are (a) the ratio of the new length to L and (b) the ratio of the new cross-sectional area to A?
Chapter9: Current And Resistance
Section: Chapter Questions
Problem 31P: Consider a wire of a circular cross-section with a radius of R = 3.00mm. The magnitude of the...
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A potential difference V is applied to a wire of cross-sectional
area A, length L, and resistivity r.You want to change the applied
potential difference and stretch the wire so that the energy dissipation
rate is multiplied by 30.0 and the current is multiplied by 4.00.
Assuming the wire’s density does not change, what are (a) the ratio
of the new length to L and (b) the ratio of the new cross-sectional
area to A?
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