A random sample of 12 students showed the following time (in hours) of sleep 4.5 5 5.5 6 6 7 7.5 7.5 8 9 5 7 If you are to get a 95% confidence interval , what is the t-value?

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A: Obtain the 90% confidence interval for the proportion of the population who subscribe to cable TV.…

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Q: Here are summary statistics for randomly selected weights of newborn​ girls: n=230​, x=30.6 ​hg,…

A: Solution-: Given: x¯=30.6, n=230, s=7.3, c=0.95 We want to construct a C.I. estimate of the mean.

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Q: A random sample of 12 students showed the following time (in hours) of sleep 4.5 5 5.5 6 6 7 7.5 7.5…

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Q: 50. Suppose a 90% confidence interval is stated as (0.3011, 0.4189). What is the sample proportion…

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A: The 95% confidence interval is (0.12, 0.18).

Q: A random sample of 12 students showed the following time (in hours) of sleep 4.5 5 5.5 6 6 7 7.5 7.5…

A: Given data  4.5,5,5.5,6,6,7,7.5,7.5,8,9,5,7 n=12

Q: 1. In a recent poll 62 out of 149 randomly chosen students at Allen High School say they plan to buy…

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Q: Here are summary statistics for randomly selected weights of newborn girls: n 188, x 30.1 hg, s =…

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Q: If n-28, 2(x-bar)-38, and s-13, construct a confidence interval at a 98% confidence level. Assume…

A: Given : Sample Size, n = 28 Sample Mean, x̄ = 38 sample standard…

Q: In a random sample of 850 consumers. 385 reported that they were able to purchase a Playstation 5.…

A: According to the given information, we have In a random sample of 850 consumers. 385 reported that…

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Q: In a sample of 100, 40 said they preferred Pepsi to coke. A 95% confidence interval for the…

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Q: For a two-tailed test, a sample size of 21 at 80% confidence, t= 1.323 2.539 1.325 2.528

A: We have to find correct option..

Q: Suppose you want to construct a 95% confidence interval for the proportion of people who will stop…

A: We have given that,  Margin of error (E) = ± 4% = ±0.04 and confidence interval = 95% Then,  We will…

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Q: Using the information from above, with p′=0.488, q′=0.512, and n=400, what is the 90% confidence…

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Q: 1. A Pew Poll conducted in 2013 surveyed a random sample of 200 adult Americans and 36 of them said…

A: Note- Since you have posted multiple questions, as per our guidelines we are supposed to answer only…

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Q: . A researcher collects a sample of 24 measurements from a population and wishes to find a​ 99%…

A: The degrees of freedom is,

Q: Suppose that the population of the scores of all high school seniors who took the SAT Math (SAT-M)…

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Q: Here are summary statistics for randomly selected weights of newborn girls: n=171, x = 31.9 hg, s =…

A: Here, n = 171, x¯=31.9, s=6.2.

Q: In a sample of 22 people, the average cost of a cup of coffee is $2.83. Assume the population…

A: Given data: Sample size  = 22 Mean = $2.83 standard deviation =  $1.01 Confidence level  = 90% To…

Q: A survey of 800 women shoppers found that 17% of them shop on impulse. What is the 98% confidence…

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Q: Which of the following would result in the widest confidence interval? O A sample size of 30 with…

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Q: Which of the following would result in the narrower confidence interval?

A: Note: The confidence interval with small confidence level has the narrower confidence interval. The…

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Q: Here are summary statistics for randomly selected weights of newborn girls: n= 217, x = 32.4 hg, s =…

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Q: Dylan wants to determine a 99 percent confidence interval for the true proportion p of high school…

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Q: A survey of 800 women shoppers found that 17% of them shop on impulse What is the 98% confidence…

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Q: Using the data below, a) generate a 95% confidence interval for the proportion of all patients with…

A: It is given that, p hat is 0.715, margin of error (E) is 0.05 and the sample size (n) is 150.  The…

Q: Give the margin of error for the 90% confidence interval for µd = µ1 – H2

A: The differences are 4, 6, 2. The mean is, d¯=∑dn=4+6+23=123=4 The standard deviation is,…

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A: The provided information are:

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Q: What is the critical t-value for finding a 95 percent confidence interval estimate from a sample of…

A: Given: Sample size (n)=18 Confidence level = 95% Level of significance = 1-confidence level = 1-0.95…

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A: Given information x = 127 N = 150

Q: 1. A survey of 800 women shoppers found that 17% of them shop on impulse. What is the 1. confidence…

A: We have to find confidence interval for the true proportion of women shoppers who shop on impulse.