A researcher compares two compounds (1 and 2) used in the manufacture of car tires that are designed to reduce braking distances for SUVs equipped with the tires. The mean braking distance for SUVs equipped with tires made with compound 1 is 7070 feet, with a population standard deviation of 13.613.6. The mean braking distance for SUVs equipped with tires made with compound 2 is 7575 feet, with a population standard deviation of 13.613.6. Suppose that a sample of 4343 braking tests are performed for each compound. Using these results, test the claim that the braking distance for SUVs equipped with tires using compound 1 is shorter than the braking distance when compound 2 is used. Let μ1μ1 be the true mean braking distance corresponding to compound 1 and μ2μ2 be the true mean braking distance corresponding to compound 2. Use the 0.10.1 level of significance. Step 3 of 5 : Find the p-value associated with the test statistic. Round your answer to four decimal places.
A researcher compares two compounds (1 and 2) used in the manufacture of car tires that are designed to reduce braking distances for SUVs equipped with the tires. The mean braking distance for SUVs equipped with tires made with compound 1 is 7070 feet, with a population standard deviation of 13.613.6. The mean braking distance for SUVs equipped with tires made with compound 2 is 7575 feet, with a population standard deviation of 13.613.6. Suppose that a sample of 4343 braking tests are performed for each compound. Using these results, test the claim that the braking distance for SUVs equipped with tires using compound 1 is shorter than the braking distance when compound 2 is used. Let μ1μ1 be the true mean braking distance corresponding to compound 1 and μ2μ2 be the true mean braking distance corresponding to compound 2. Use the 0.10.1 level of significance.
Find the p-value associated with the test statistic. Round your answer to four decimal places.
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