A researcher compares two compounds (1 and 2) used in the manufacture of car tires that are designed to reduce braking distances for SUVS equipped with the tires. SUVS equipped with tires using compound 1 have a mean braking distance of 43 feet and a standard deviation of 6.6 feet. SUV equipped with tires using compound 2 have a mean braking distance of 50 feet and a standard deviation of 11.8 feet. Suppose that a sample of 61 braking tests are performed for each compound. Using these results, test the claim that the braking distance for SUVS equipped with tires using compound 1 is shorter than the braking distance when compound 2 is used. Let 4i be the true mean braking distance corresponding to compound 1 and uy be the true mean braking distance corresponding to compound 2. Use the 0.01 level of significance. Step 3 of 4: Determine the decision rule for rejecting the null hypothesis Ho. Round the numerical portion of your answer to two decimal places.

A researcher compares two compounds (1 and 2) used in the manufacture of car tires that are designed to reduce braking distances for SUVS equipped with the tires. SUVS equipped with tires using compound 1 have a mean braking distance of 43 feet and a standard deviation of 6.6 feet. SUV equipped with tires using compound 2 have a mean braking distance of 50 feet and a standard deviation of 11.8 feet. Suppose that a sample of 61 braking tests are performed for each compound. Using these results, test the claim that the braking distance for SUVS equipped with tires using compound 1 is shorter than the braking distance when compound 2 is used. Let 4i be the true mean braking distance corresponding to compound 1 and uy be the true mean braking distance corresponding to compound 2. Use the 0.01 level of significance. Step 3 of 4: Determine the decision rule for rejecting the null hypothesis Ho. Round the numerical portion of your answer to two decimal places.

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A researcher compares two compounds (1 and 2) used in the manufacture of car tires that are designed to reduce braking distances for SUVS equipped with the tires.
SUVS equipped with tires using compound 1 have a mean braking distance of 43 feet and a standard deviation of 6.6 feet. SUVS equipped with tires using compound 2
have a mean braking distance of 50 feet and a standard deviation of 11.8 feet. Suppose that a sample of 61 braking tests are performed for each compound. Using
these results, test the claim that the braking distance for SUVS equipped with tires using compound 1 is shorter than the braking distance when compound 2 is used.
Let ui be the true mean braking distance corresponding to compound 1 and uz be the true mean braking distance corresponding to compound 2. Use the 0.01 level of
significance.
Step 3 of 4: Determine the decision rule for rejecting the null hypothesis Ho. Round the numerical portion of your answer to two decimal places.
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ISBN:

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