A sample of graphite sealed under 0.458 atm of CO2(g) at 1080 K forms CO(g) and makes Ptot = 0.757 atm at eq≡m. Find KP: C(s) + CO2(g) 2 CO(g) KP = Peq(CO)2
A sample of graphite sealed under 0.458 atm of CO2(g) at 1080 K forms CO(g) and makes Ptot = 0.757 atm at eq≡m. Find KP: C(s) + CO2(g) 2 CO(g) KP = Peq(CO)2
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter8: Thermochemistry
Section: Chapter Questions
Problem 90QAP: Consider a metal ion A2+ and its nitrate salt, In an experiment, 35.00 mL of a 0.217 M solution of...
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A sample of graphite sealed under 0.458 atm of CO2(g) at 1080 K forms CO(g) and makes Ptot = 0.757 atm at eq≡m. Find KP:
C(s) + CO2(g) 2 CO(g) KP = Peq(CO)2
Set up an ICE Table:
Use other geven data to calculate the unknown:
Ptot = 0.757 atm = Peq(CO2) + Peq(CO)= 0.458 – x + 2x = 0.458+x
x=o.299 atm
Peq(CO2) = 0.458 – x = ______ atm
Peq(CO) = 2x = ______ atm
Kp=Peq(CO)2 / Peq(CO2) =
_____^2 atm2/ _____ atm = ______ atm
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