A solution is prepared by adding 0.10 mole of Ni(NH, ),Cl, to 0.50 Lof 3.4 M NH, Calculate Ni (NH,)," and Ni" 5.5 x 10, That is, in this solution. Kesa for Ni (NH,)," NI (NH,),"] 5.5 x 10"= for the overall reaction Ni* (ag) + 6NH, (aq) Ni (NH, )," (aq) M. [NP] -[ -HN) IN] Submit Answer Try Another Version 1 item attempt remaining

Introductory Chemistry: An Active Learning Approach
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Author:Mark S. Cracolice, Ed Peters
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Chapter18: Chemical Equilibrium
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A solution is prepared by adding 0.10 mole of Ni(NH, )eCl, to 0.50 L of 3.4 M NH, Calculate Ni (NH,)," and Ni
in this solution. Ksa for Ni (NH,),"
5.5 x 10, That is,
Ni (NH,),"]
5.5 x 10"
for the overall reaction
2+
Ni* (ag) + 6NH, (aq) Ni (NH, )," (ag)
[NI (NH,),"]-C
M.
Submit Answer
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1 item attempt remaining
Transcribed Image Text:A solution is prepared by adding 0.10 mole of Ni(NH, )eCl, to 0.50 L of 3.4 M NH, Calculate Ni (NH,)," and Ni in this solution. Ksa for Ni (NH,)," 5.5 x 10, That is, Ni (NH,),"] 5.5 x 10" for the overall reaction 2+ Ni* (ag) + 6NH, (aq) Ni (NH, )," (ag) [NI (NH,),"]-C M. Submit Answer Try Another Versian 1 item attempt remaining
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