A solution is prepared by dissolving 16.2 g ammonium sulfate in enough water to make 260.0 mL of stock solution. A 35.00-mL sample of this stock solution is added to 60.00 mL of water. Calculate the concentration of ammonium ions and sulfate ions in the final solution. Assume that the volumes are additive. Concentration of ammonium ions = M Concentration of sulfate ions = M

Chemistry: Principles and Practice
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Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
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Chapter4: Chemical Reactions In Solution
Section: Chapter Questions
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A solution is prepared by dissolving 16.2 g ammonium sulfate in enough water to make 260.0 mL of stock solution. A 35.00-mL sample of this stock solution is added to 60.00 mL
of water. Calculate the concentration of ammonium ions and sulfate ions in the final solution. Assume that the volumes are additive.
Concentration of ammonium ions =
Concentration of sulfate ions =
M
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Transcribed Image Text:[References] A solution is prepared by dissolving 16.2 g ammonium sulfate in enough water to make 260.0 mL of stock solution. A 35.00-mL sample of this stock solution is added to 60.00 mL of water. Calculate the concentration of ammonium ions and sulfate ions in the final solution. Assume that the volumes are additive. Concentration of ammonium ions = Concentration of sulfate ions = M Suhmit Answer Toy Another Version
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