A solution is prepared by mixing 25.0 mL of 0.34 M NH3 (pKp=4,74) and 21.0 mL of 0.95 M HCN (pKa-9.21). What is concentration of HCN at equilibrium given the reaction below? NH3 (aq) + HCN (aq) → NH4* (aq) + CN" (aq) Numeric Response
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- What is the concentration of NaOH (sodium hydroxide), in ppm (m/m), in a solution prepared by dissolving 32 mg of NaOH in 5.8 kg of water? Report your result in decimal notation and to the proper number of significant figures. All numbers are measured. a) 0.18 ppmb) 1.8 ppmc) 0.55 ppmd) 5.5 ppme) no correct responseA 190.00 mL solution of 0.00300 M AB4 is added to a 340.00 mL solution of 0.00265 M CD5. What is pQsp for AD4? Answer: (11.251)From the initial concentration of the acid and the measured ph, calculate Ka and pKa for the unknown acid. Also find the percent error 0.050 M unknown acid pH= 4:34 pKa(actual) = 6.74
- 1. AST ELIN nasal spray contains 0.1% azelastine hydrochloride and 125 mcg/mL of benzalkonium chloride as a preservative. A container is capable of delivering 200 metered sprays of 0.137 mL each. Calculate the quantity, in micrograms, of azelastine hydrochloride in each spray.Calculate the ratio strength of benzalkonium chloride in the preparation. Answer #1 = ___ mcg Answer #2 = ___ Please show solution. thank you.Benzoic acid is an organic acid with a K₂ = 6.47 x 10-5 at 25.0°C. Calculate the pK₂ of benzoic acid at 25.0 °C. Report your answer to two decimal places. Example: 7.00 Type your answer. 9Analytical Method Validation of 1N Sodium Hydroxide What is the result of the titration or the result of the experiment? Weighed 2 samples of sodium hydroxide 1st weight = 40.0109 g 2nd weight = 30.0183 g Prepared 3 filtered water in the volumetric flask Used carbon free water Weight for the primary standards potassium biphthalate 1st Weight - 5.0305 g 2nd Weight - 5.0015 g 3rd Weight - 5.0034 g 4th Weight - 5.006 g Added 75 mL of water 1st titration 1st trial =34.5 mL 2nd trial =34.2 mL 3rd trial =34.5 mL 4th trial o=34.5 mL 2nd titration 1st trial =21 mL 2nd trial =21.5 mL 3rd trial = 21.5 mL 4th trial = 21.5 mL
- magnesium hydroxide, Mg(OH)2, found in milk of magnesia, has a solubility of 7.05x10-3 gL-1 at 25ºC. Calculate the Ksp for Mg(OH)2 with a tolerance of +8 (Please type answer)Answer 3,4,5 plsanswer the question "calculate the number of moles and mass (in grams) of cobalt nitrate in the volume was 250 mL" given the experiment finding the concentration of an unknown solution of Cobalt Nitrate (Co(NO4)2). results Sample Number Concentration of Copper(II) Sulphate (mM) Measured Absorbance 1 0 0 2 50 0.12 3 100 0.24 4 150 0.35 5 200 0.47 Unknown 40 0.09
- Given the following unbalanced response:NO2-+MnO4-+H+ NO3-+Mn2++H2OWhat is the number of electrolyte molecules passing through the reaction? A. 1 B. 2 C. 5 D. 10% Recovery of Ferrocene = (0.0459/0.102g) x 100 = 45% % Recovery of Acetylferrocene = (0.054/0.102g) x 100 = 52.9 % Question 1 : According to the data, what does % recovery means? can we say that acetylferrocene has a higher % recovery because the proportion of the amount of acetylferrocene present in the analytical portion of the 50:50 mixture is 7.9% higher than Ferrocene????? Question 2 :Am I calculating my %recovery correctly????A 50.00 (±0.03) mL portion of an HCl solution required 29.71(±0.03) mL of 0.01963(±0.0030) M Ba(OH)2 to reach an end point with bromocresol green indicator. The molar concentration of the HCl is calculated using the equation below (attached image): a.) Calculate the uncertainty of the result (absolute error). M=0.02333(±?????) M b.) Calculate the coefficient of variation for the result. CV= (Sy/y) x 100%