3Ce+ (aq) + Bi(s)+ H2O(1)→3Ce3+ (aq) + BiO+ (aq)+2H+(aq) Express the equilibrium constant to two significant digits. ? K = 2.9 • 1065 Submit Previous Answers Request Answer • Part C N2H5+ (aq) + 4Fe(CN),³-(aq)→N2(g)+ 5H†(aq) +4Fe(CN)6ª-(aq) Express the equilibrium constant to two significant digits. ? 39 K = 8.6 • 10"

General Chemistry - Standalone book (MindTap Course List)
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
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Chapter21: Chemistry Of The Main-group Elements
Section: Chapter Questions
Problem 21.164QP
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Question
Using the standard reduction potentials listed in
Appendix E in the textbook, calculate the equilibrium
constant for each of the following reactions at 298 K.
3Ce+ (aq) + Bi(s)+ H2O(1)→3CE+ (aq) + BiO+ (aq) + 2H+(aq)
Express the equilibrium constant to two significant digits.
Πν ΑΣφ
?
K = 2.9 • 1065
Submit
Previous Answers Request Answer
Part C
N2H5+(aq) + 4Fe(CN)6³-(aq)→N2(g) + 5H†(aq) +4Fe(CN),4-(aq)
Express the equilibrium constant to two significant digits.
nν ΑΣφ
?
K = 8.6 • 103°
Transcribed Image Text:Using the standard reduction potentials listed in Appendix E in the textbook, calculate the equilibrium constant for each of the following reactions at 298 K. 3Ce+ (aq) + Bi(s)+ H2O(1)→3CE+ (aq) + BiO+ (aq) + 2H+(aq) Express the equilibrium constant to two significant digits. Πν ΑΣφ ? K = 2.9 • 1065 Submit Previous Answers Request Answer Part C N2H5+(aq) + 4Fe(CN)6³-(aq)→N2(g) + 5H†(aq) +4Fe(CN),4-(aq) Express the equilibrium constant to two significant digits. nν ΑΣφ ? K = 8.6 • 103°
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