A strand of DNA has the base sequence of AGCCAT (written in the 5' to 3' direction). What is the base sequence for the complementary strand in the 5' to 3' direction? a. TCGGTA b. UCGGUA c. TACCGA d. ATGGCT

A strand of DNA has the base sequence of AGCCAT (written in the 5' to 3' direction). What is the base sequence for the complementary strand in the 5' to 3' direction? a. TCGGTA b. UCGGUA c. TACCGA d. ATGGCT

Name: . A strand of DNA has the base sequence of AGCCAT (written in the 5' t
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Description: . A strand of DNA has the base sequence of AGCCAT (written in the 5' to 3' direction). What is the base sequence for the complementary strand in the 5' to 3' direction?a. TCGGTAb. UCGGUAc. TACCGAd. ATGGCT In humans, the codon CCC codes for the amino

Concepts of Biology

1st Edition

ISBN:9781938168116

Author:Samantha Fowler, Rebecca Roush, James Wise

Publisher:Samantha Fowler, Rebecca Roush, James Wise

Chapter9: Molecular Biology

Section: Chapter Questions

Problem 6RQ: A promoter is ______. a. a specific sequence of DNA nucleotides b. a specific sequence of RNA...

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Which event contradicts the central dogma of molecular biology? a. Poly-A polymerase enzymes process mRNA in the nucleus. b. Endonuclease enzymes splice out and repair damaged DNA. c. Scientists use reverse transcriptase enzymes to make DNA from RNA. d. Codons specifying amino acids are degenerate and universal.
Now imagine that a mutation occurred at the first G in the DNA sequence above and the G became a C. How would this affect the mRNA and the amino acid for that codon? Old DNA codon Old RNA codon Old amino acid New DNA codon New mRNA codon New amino acid T T G T T C This would be an example of which type of a point mutation?__________________________
Finally, imagine that a mutation occurred in the codon below and an A was inserted between the two Ts. How would this affect the mRNA and the amino acid for that codon? Old DNA codon Old RNA codon Old amino acid New DNA codon New mRNA codon New amino acid T T G T A T G This would be an example of which type of a mutation?__________________________
f the template strand of DNA has the sequence 5’-TCTAGGACT-3’, what will the sequence of the transcribed RNA be? A. 5’-AGAUCCUGA-3’ B. 5’-UCAGGAUCU-3’ C. 5’-AGUCCUAGA-3’ D. 5’-AGATCCTGA-3’ E. 5’-UCAGGATCT-3’
Now imagine that a mutation occurred in the second T of the codon below and the T became a G. How would this affect the mRNA and the amino acid for that codon? Old DNA codon Old RNA codon Old amino acid New DNA codon New mRNA codon New amino acid T T G T G G This would be an example of which type of a point mutation?__________________________
Choose the DNA sequence from which this mRNA sequence wastranscribed: 5′-AUACGAUUA-3′.a. 3′-TATGCTAAT-5′ c. 3′-UAUCGUAAU-5′b. 3′-UTUGCUTTU-5′ d. 3′-CTCAGCTTC-5′
What is the base sequence of a mRNA strand that is complementary to the DNA sequence 5'-ATCGGATTC-3' sequence? a5'-ATCGGATTC-3' b5'-GAAUCCGAU-3' c5'-GAATCCGAT-3' d5'-UAGCCUAAG-3'
The figure below shows a polynucleotide:a) Label the 5' and the 3' end of the sequenceb) If a nucleotide were added to this polynucleotide, which end would it be added to?c) Is this an RNA or DNA strand? How do you know?
What is the function of the enzyme DNA polymerase? To build a polypeptide using mRNA as a template To build a strand of DNA using DNA as a template To build a strand of DNA using a polypeptide as a template To build a strand of mRNA using DNA as a template
The template strand of DNA is 3’AGGATGCACGTAC5’ The sequence of the mRNA that is made from this DNA is: A) 5’UCCUACGUGCAUG3’ B) 5'AGGATGCACGTAC 3’ C) 3’UCCUACGUGCAUG5’ D) 3’AGGAUGCACGUAC5’ E) 5’AGGAUGCACGUAC3’
Which rRNA plays a major role in the aligning of the transcript in the ribosome of prokaryotes? A. 28S rRNA B. 23S rRNA C. 16S rRNA D. 18S rRNA
Shown below is a DNA coding strand. A base (*G*) mutates to Adenine (A). What will be the resulting amino acid sequence as a result of the mutation? What type of mutation occured? Hint: Determine the template, then first determine the amino acid sequence before the mutation, and then determine the amino acid sequence after the mutation. Show how you got your answer. 5' T-A-C-T-T-C-C-A-*G*-C-C-G-C-T-C 3'