A student wishes to determine the heat capacity of a coffee-cup calorimeter. After she mixes 107.5 g of water at 62.7°C with 107.5 g of water, already in the calorimeter, at 20.9°C, the final temperature of the water is 35.0°C. Calculate the heat capacity of the calorimeter in J/K. Use 4.184 J/g°C as the specific heat of water. Enter a number to 1 decimal place.

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter6: Thermochemistry
Section: Chapter Questions
Problem 64E: A 110.-g sample of copper (specific heat capacity = 0.20 J/C g) is heated to 82.4C and then placed...
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A student wishes to determine the heat capacity of a coffee-cup calorimeter. After she mixes 107.5
g of water at 62.7°C with 107.5 g of water, already in the calorimeter, at 20.9°C, the final
temperature of the water is 35.0°C. Calculate the heat capacity of the calorimeter in J/K. Use 4.184
J/g°C as the specific heat of water. Enter a number to 1 decimal place.
Transcribed Image Text:A student wishes to determine the heat capacity of a coffee-cup calorimeter. After she mixes 107.5 g of water at 62.7°C with 107.5 g of water, already in the calorimeter, at 20.9°C, the final temperature of the water is 35.0°C. Calculate the heat capacity of the calorimeter in J/K. Use 4.184 J/g°C as the specific heat of water. Enter a number to 1 decimal place.
Expert Solution
Step 1: Introduction

Heat capacity of a calorimeter is the amount of heat energy absorbed by the calorimeter per Kelvin raise in temperature.

Heat capacity is an extensive property. It depends upon amount of substance present.

Given that,

Mass of water present initially in calorimeter = 107.5 g

Initial temperature of water in calorimeter = 20.9°C

Mass of water added = 107.5 g

Initial temperature of water added = 62.7°C

Final temperature of total water = 35°C

Water added to the calorimeter is initially at higher temperature and is cooled to a lower temperature. So, heat energy is lost by this system.

Water initially present in calorimeter has raised in temperature. So, heat energy is gained by this system.

By substracting the amount of heat gained by the system from the amount of heat lost by the system, the amount of heat energy lost to calorimeter is determined.

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