A survey​ asked, "How many tattoos do you currently have on your​ body?" Of the 1202 males​ surveyed, 180 responded that they had at least one tattoo. Of the 1034 females​ surveyed, 147 responded that they had at least one tattoo. Construct a 95​% confidence interval to judge whether the proportion of males that have at least one tattoo differs significantly from the proportion of females that have at least one tattoo. Interpret the interval.   Let p 1 represent the proportion of males with tattoos and p 2 represent the proportion of females with tattoos. Find the 95% confidence interval for p 1 -p 2p

Q: 1. Customers randomly selected at a grocery store included 172 women and 45 men. 74 of the women and…

A: Given: Number of women (n1) = 172 Number of men (n2) = 45 Number of women used coupons (x1) = 74…

Q: A survey​ asked, "How many tattoos do you currently have on your​ body?" Of the 1215 males​…

A:

Q: Out of 100 people sampled, 16 have tried marijuana. Based on this, construct a 95% confidence…

A: Obtain the 95% confidence interval for the true population proportion of people who have tried…

Q: A survey asked, How many tattoos do you currently have on your body?" Of the 1202 males surveyed,…

A: Given X1=188 X2=137 n1=1201 n2=1027 99% CI

Q: A survey asked, "How many tattoos do you currently have on your body?" Of the 1209 males surveyed,…

A:

Q: 2. A nutritionist wants to know the population proportion of Grade 1 learners who eat vegetables.…

A: We have given thatn = 1200x = 200p̂ = x/n = 200/1200 = 0.167Significance level (α) = 1 - 0.95 = 0.05

Q: survey​ asked, "How many tattoos do you currently have on your​ body?" Of the 1211 males​surveyed,…

A: We have to create 99% confidence interval for difference in proportion and we have to find if…

Q: In a survey of 1,200 social media users, 56% said it is not okay to be friends with your boss.…

A:

Q: 3. Cyber Monday Shopping A survey of 1000 U.S. adults found that 33% of people said that they would…

A: It is given that Sample size n = 1000 Sample proportion = 33% = 0.33 The critical value of t at 95%…

Q: A survey asked, "How many tattoos do you currently have on your body?" Of the 1223 males surveyed,…

A: From the given information, 1223 males surveyed, 188 responded that they had at least one tattoo.…

Q: In a random sample of 500 people eating lunchbat a cafeteria on various fridays, it was found that…

A: Given X=160 n=500 P=X/n

Q: A survey​ asked, "How many tattoos do you currently have on your​ body?" Of the 12231223 males​…

A: We need to construct the 90%90\%  confidence interval for the difference between population…

Q: Out of 300 people sampled, 273 had kids. Based on this, construct a 99% confidence interval for the…

A:

Q: random digit dialing telephone system was used to conduct a survey asking 3230 city residents; "do…

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Q: Find the 68% confidence interval for the percentage of leaky diapers with a sample of 100 diapers…

A: Let X be the number of defective diapers and n is the number of diapers. From the given information,…

Q: In a survey of 50,00 people, 80% indicated that they listened to their favorite radio station…

A: Hern= 5000 P^ = 0.80 We have to construct 95% ci for p

Q: In one city, 59.6% of the 1500 students surveyed said they eat at the school cafeteria. Find the 95%…

A: Given, Sample size=n=1500 p^=0.596 α=0.05

Q: If n=240 and ˆpp^ (p-hat) =0.91, find the margin of error at a 90% confidence level Give your…

A:

Q: If n=590 and p=0.93, construct a 90% confidence interval.

A: Express the expression for the confidence interval. C.I=p±Z*p(1-p)n Here, Z* is the critical value .…

Q: A survey asked, "How many tattoos do you currently have on your body?" Of the 1218 males surveyed,…

A: Given Information:              n1=1218a1=191p1=1911218=0.1568n2=1011a2=191p2=1911011=0.1246

Q: A survey asked, "How many tattoos do you currently have on your body?" Of the 1244 males surveyed,…

A: Confidence interval give a range of plausible values for unknown parameters of population. The width…

Q: If n = 560 and ˆpp^ (p-hat) = 0.25, construct a 99% confidence interval.

A: Calculations: x=140 and N= 560

Q: A survey​ asked, "How many tattoos do you currently have on your​ body?" Of the 1238 males​…

A:

Q: A survey asked, "How many tattoos do you currently have on your body?" Of the 1232 males surveyed,…

A: Given that: Total number of males surveyed, n1=1232 Number of male respondent with at least one…

Q: A survey​ asked, "How many tattoos do you currently have on your​ body?" Of the 1204 males​…

A:

Q: 9. A survey found that out of 900 workers, 150 said they were interrupted by frank phone calls. Find…

A:

Q: A survey asked, "How many tattoos do you currently have on your body?" Of the 1218 males surveyed,…

A:

Q: 2. In a survey of 1024 US adults, 287 said that their favorite sport to watch is football. a. Find a…

A: It is given that the survey contains 1024 US adults and the number of US adults who favorite sport…

Q: A research institute poll asked respondents if they felt vulnerable to identify a theft. In the poll…

A: Given,n=1000x=501p^=xnp^=5011000=0.5011-p^=1-0.501=0.499α=1-0.99=0.01α2=0.005Z0.005=2.58    (from…

Q: If n=270 and ˆpp^ (p-hat) =0.59, find the margin of error at a 99% confidence level Give your…

A: Given  n=270, pcap=0.59, alpha=0.01 Zcritical=2.578 at alpha=0.01 We want to find margin of error

Q: A survey​ asked, "How many tattoos do you currently have on your​ body?" Of the 1227 males​…

A:

Q: In a sample of 900 people, 378 say they snooze the alarm more than once in the morning. Find a 95%…

A: Given,   The sample proportion is,

Q: A survey asked, "How many tattoos do you currently have on your body?" Of the 1247 males surveyed,…

A: From the provided information,

Q: If n = 520 and p^ = 0.85, construct a 99% confidence interval

A: Here, n = 520 and p hat = 0.85.

Q: A survey​ asks, "If the husband in a family wants​ children, but the wife decides that she does not…

A: We have to create 99% confidence interval for the population proportion.

Q: A survey asked, "How many tattoos do you currently have on your body?" Of the 1217 males surveyed,…

A:

Q: After surveying 625 potential voters polled, you find out that 325 support candidate X and 300…

A: The sample proportion confidence interval is, p^±Zp^(1-p^)nwhere, p^ = the sample proportion…

Q: A survey of 360 college seniors found that 305 wish they had spent more time studying. Find a 94%…

A: Givensample size(n)=360x=305p^=xn=305360=0.8472confidence interval = 94%

Q: A survey​ asked, "How many tattoos do you currently have on your​ body?" Of the 1205 males​…

A: Given that…

Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

A: Given : Sample Size, n = 316 Number of successes, x = 112 confidence level,c=0.99…

Q: A survey asked, "How many tattoos do you currently have on your body?" Of the 1233 males surveyed,…

A: We have given that, For the males:- X1 = 183 and n1 = 1233 For the females :- X2 = 139 and n2 = 1042…

Q: Construct a 99% confidence interval for the true proportion of all car license applications that…

A: Given Information:x=25n=155c=99%=0.99

Q: A survey found that out of 800 workers, 150 said they were interrupted by frank phone calls. Find…

A: Given,n=800x=150p^=xnp^=150800=0.18751-p^=1-0.1875=0.8125α=1-0.95=0.05α2=0.025Z0.025=1.96

Q: 2. A survey found that out of 900 workers, 150 said that they were interrupted by frank phone calls.…

A: In question, We have given the number of favorable cases 150 and sample size 900 then we'll find 95%…

Q: A student was asked to find a 95% confidence interval for the proportion of students who take notes…

A: It is given that a student was asked to find a 95% confidence interval for the proportion of…

Q: A survey asked, "How many tattoos do you currently have on your body?" Of the 1207 males surveyed,…

A:

Q: Out of 300 people sampled, 78 had kids. Based on this, construct a 99% confidence interval for the…

A:

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.