A system of four particles moves along one dimension. The center of mass of the system is at rest, and the particles do not interact with any objects outside of the system. Find the velocity v4 of particle 4 at t = 2.99 s given the details for the motion of particles 1, 2, and 3. particle 1: mi = 1.33 kg, vi (1) = (6.97 m/s) + (0.365 m/s2) x t particle 2: m2 = 3.53 kg, vz (1) = (8.93 m/s) + (0.357 m/s2) xt particle 3: m3 = 4.85 kg, vz (1) = (6.77 m/s) + (0.405 m/s) x 1 particle 4: m4 = 4.91 kg

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