The vector position of a 4.00 g particle moving in the xy plane varies in time according to r, = (3î + 3j)t + 2ĵt² where t is in seconds and r is in centimeters. At the same time, the vector position of a 5.55 g particle varies as r, = 3î - 2ît² – 6ĵt. (a) Determine the vector position (in cm) of the center of mass of the system at t = 2.60 s. cm = -5.975i – 0.286j cm (b) Determine the linear momentum (in g · cm/s) of the system at t = 2.60 s. p = g• cm/s (c) Determine the velocity (in cm/s) of the center of mass at t = 2.60 s. cm/s ст (d) Determine the acceleration (in cm/s²) of the center of mass at t = 2.60 s. cm/s? 'cm (e) Determine the net force (in µN) exerted on the two-particle system at t = 2.60 s. Fnet -4.8 i+ 2.1 j µN =

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