A system of four particles moves along one dimension. The center of mass of the system is at rest, and the particles do notinteract with any objects outside of the system. Find the velocity v4 of particle 4 at t = 2.83s given the details for the motion ofparticles 1, 2, and 3.particle 1:m1 = 1.69 kg,vi (t) = (6.09 m/s) + (0.299 m/s² ) × tparticle 2:m2 = 3.05 kg,v2 (t) = (9.15 m/s) + (0.525 m/s² ) × tparticle 3:m3 = 4.37 kg,V3 (t) = (6.99 m/s) + (0.111 m/s²) xtparticle 4:m4 = 5.27 kgU4 =m/s

Given: Required: The velocity of the particle 4 at time t = 2.83 sec as all the…

Answered: A system of four particles moves along…

Physics for Scientists and Engineers with Modern Physics

10th Edition

ISBN:9781337553292

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter9: Linear Momentum And Collisions

Section: Chapter Questions

Problem 53CP

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