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Social ScienceA tensile test specimen has a gage length = 3.0 in anddiameter 0.75 in. Yielding occurs at a load of 38,000 lb. Thecorresponding gage length 3.01 03 in (neglect the 0.2 percentyield point). The maximum load of 54,000 lb is reached at a gagelength 3.453 in. Determine the tensile strength (round to thenearest whole Ksi)38
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A tensile test specimen has a gage length = 3.0 in and diameter 0.75 in. Yielding occurs at a load of 38,000 lb. The corresponding gage length 3.01 03 in (neglect the 0.2 percent yield point). The maximum load of 54,000 lb is reached at a gage length 3.453 in. Determine the tensile strength (round to the nearest whole Ksi) 38
Expert Answer
In order to determine the tensile strength of the specimen, the maximum load and area of cross section of the specimen are required.
Determine the area of cross-section, A of the specimen, where the diameter of the cross-section, d is given.
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(d A = 4 (0.75 in) 2 4 0.4417 in2
Use the expression for Tensile Strength and substitute the provided and determined values.
Convert the value of tensile strength f...
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1 lb/in2 0.001 Ksi Therefore, 122254.94 lb/in2 (122254.94) ( 0.00 1) Ksi 122254.94 lb/in2 = 122.25 Ksi
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