A three-bar frame is loaded and supported as Determine the internal resisting forces shown in Fig. and moment transmitted by Section aa in bar ABC. 2.5 ft 2.5 ft 4 ft bb+ 2ft 800 ft-lb 2 ft 2 ft E 2000 lb
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- Find the internal force system acting on section 3 for the pin-connected frame. a P = 255 N (C), V = 0, M = 29.8 N · m b P = 255 N (T), V = 0, M = 29.8 N · m c P = 255 N (C), V = 0, M = 92.8 N · m d P = 525 N (C), V = 0, M = 29.8 N · mUnder non-uniform and slippery road conditions, two forces (u and w), shown in the figure (image 1), are performed on the truck's rear wheels, which have a limited slip rear differential. Choose the alternatives that are true: (data: u = 92lbf and w =57lbf) (obs1.0: 1''= 1 in = 25,4mm) (obs2.0: 1lbf = 4,448N) a) the force vector resulting from the two forces is -149i [lbf] b) the resultant of the two forces has an intensity equal to 149lbf c) the ordinate of the point of intersection of the line of action of the resultant of this system of forces with the y axis is 7.05in d) adopting the counterclockwise direction as positive, the total moment of the two forces in relation to point g is equal to -1050lbf.in e) the total moment vector in relation to the G point is equal to -1050i [lbf.in]nonuniform beam 4.50 m long and weighing 1.40 kNmakes an angle of 25.0° below the horizontal. It is held in position bya frictionless pivot at its upper right end and by a cable 3.00 m fartherdown the beam and perpendicular to it . The center ofgravity of the beam is 2.00 m down the beam from the pivot. Lightingequipment exerts a 5.00 kN downward force on the lower left end ofthe beam. Find the tension T in the cable and the horizontal and verticalcomponents of the force exerted on the beam by the pivot. Start bysketching a free-body diagram of the beam.
- Topic: Couples, Resultant of Force Systems & Equilibrium If F1 = 10N, F2 = 15N, F3 = 8N, F4 = 10N, F5 = 18N, and the length of te side of a red square is 1m. Calculate magnltude (+ for CCW, - for CW) of the resuItant moment (N-m) about point A. Calculate the magnitude of the reItant f0rce (N). (Answer: 50.80Nm, 20.33N)A 415 kg safe is hanging from the apparatus below. Determine the tension in the cable. Dimension a=1.9 m and dimension b=2.5 m. The mass of the beam is 85 kg. Use g = 10 N/kg. Hint: Take torques about the hinge and use the perpendicular lever arm version of the torque equation (the sin theta version will work but will require more calculation).A sign of weight 2280 N is supported as shown by a ball and socket support at A and two cables BC and AD 1- Tension in cable BC is (N) : (a. 4560 - b. 6840 - c. 5700 - d. 7980 - e. 9120 ) 2- Tension in cable AD is (N): (a. 10260 - b. 13680 - c. 15960 - d. 18240 - e. 10640 ) 3-Magnitude of x-component of reaction at O is (N): (a. 5700 - b. 6840 - c. 7980 - d. 9120 - e. 10260 ) 4- Find Magnitude of y-component of reaction at O is (N) 5- Find Magnitude of z-component of reaction at O is (N)
- The bar AC is supported by a joint at A and a pin B that is free to slide in the same direction (alpha) of the bar. A bar is connected at C and a force is applied in the theta direction. Consider that L1 = 2.7 m, L2 = 1.7 m, alpha = 13 °, theta = 25 °, and P = 68 kN. Determine the magnitude of the force (kN) on pin B.Application of Equilibrium Solve for the value of unknown variables Given : P1 = 6.85 KN P2 = 4.65 KN W1 = 6.15 KN/m Unknowns : RAy , RAx ,RBy , MA What is the value of internal shear 2.50m to the right of support A3. A mobile is constructed of light rods, light strings, and beach souvenirs as shown in the figure below. If m4 = 12.0 g, find values (in g) for the following. (Let d1 = 4.50 cm, d2 = 6.10 cm, d3 = 2.40 cm, d4 = 4.40 cm, d5 = 2.90 cm, and d6 = 3.50 cm.) 4. One end of a uniform 3.70-m-long rod of weight Fg is supported by a cable at an angle of ? = 37° with the rod. The other end rests against the wall, where it is held by friction as shown in the figure below. The coefficient of static friction between the wall and the rod is μs = 0.495. Determine the minimum distance x from point A at which an additional object, also with the same weight Fg, can be hung without causing the rod to slip at point A.
- A steel plate of dimensions 2.5 x 1.5 x 0.08 m and weighing 23.1 kN is hoisted by steel cables with lengths L1 = 3.2 m and L2 = 3.9 m that are each attached to the plate by a clevis and pin (see figure). The pins through the clevises are 18 mm in diameter and are located 2.0 m apart. The orientation angles are measured to be s = 94.4' and a = 54.9° For these conditions, first determine the cable forces T1 and T2, then find the average shear stress Taver in both pin 1 and pin 2, and then the average bearing stress ?? between the steel plate and each pin. Ignore the weight of the cables.Dr. Alexander is holding a briefcase with straight arm. Assume weight of the briefcase FB = 35 N, weight of the forearm FFA = 10 N, weight of the upper arm FUA = 15 N, moment arm of FB = 0.45 m, moment arm of FFA = 0.30 m, moment arm of FUA = 0.11 m, and moment arm of Fm = 0.03 m. Also, FM is 35 degrees above the horizontal. Calculate (1) muscle force FM, and (2) joint reaction forces Fj,x and Fj,yA torsional moment of 1.1 kN.m is applied to a circular shaft 4 cm in diameter and 150 cm in length, calculate: a) the maximum tension on the shaft; b) the maximum torsional angle, given that G=85 GPa.