a) [TiCI(Cp)2(CN)] Oxidation state of metal: X+(-1)+0+(-1)=0 X=+2 Ligand: chloro, cyclopentadiene, cyano [TİCI(Cp)2(NH3)]CI X(-1)+2(0)+0=+1 X-1=+1| X=+2 Ligand: chloro, cyclopentadiene, ammine Stability: [TiCl(Cp)2(CN)] is more stable due to strong field ligand (CN-) and sigma and pi back bonding exist in this complex. So, [TiCI(Cp)2(NH3)]Cl is less stable compare to [TiC(Cp)2(CN)].

Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter19: Complex Ions
Section: Chapter Questions
Problem 25QAP
icon
Related questions
Question

Explain a little more why the complex is chosen to be more stable.

a)
[Tic((Cp)2(CN)]
Oxidation state of metal:
X+(-1)+0+(-1)=0
X=+2
Ti2-
Ligand: chloro, cyclopentadiene, cyano
[TİCI(Cp)2(NH3)]ci
X(-1)+2(0)+0=+1
X-1=+1|
X=+2
Ligand: chloro, cyclopentadiene, ammine
Stability: [TiCI(Cp)2(CN)] is more stable due to strong field ligand (CN-) and sigma and
pi back bonding exist in this complex. So, [TicI(Cp)2(NH3)]Cl is less stable compare to
[TicI(Cp)2(CN)].
Transcribed Image Text:a) [Tic((Cp)2(CN)] Oxidation state of metal: X+(-1)+0+(-1)=0 X=+2 Ti2- Ligand: chloro, cyclopentadiene, cyano [TİCI(Cp)2(NH3)]ci X(-1)+2(0)+0=+1 X-1=+1| X=+2 Ligand: chloro, cyclopentadiene, ammine Stability: [TiCI(Cp)2(CN)] is more stable due to strong field ligand (CN-) and sigma and pi back bonding exist in this complex. So, [TicI(Cp)2(NH3)]Cl is less stable compare to [TicI(Cp)2(CN)].
b)
[IrMe(PMe3)4]
Oxidation state of metal:
X+(-1)+(0)=0
X=+1
Irt+
Ligand: methyl anion, trimethylphosphine,.
[Ir(C=C-Ph)(PME3)4]
X(-1)+4(0)=+1
X-1=+1
X=+1
Irl+
Ligand: phenylacetylene anion, trimethyl phosphine
Stability: [Ir(C=C-Ph)(PME3)4] is more stable due to phenylacetylene pi back bonding.
So, [Ir(C=C-Ph)(PME3)4] is less stable compare to [IrMe(PMe3)4]
Transcribed Image Text:b) [IrMe(PMe3)4] Oxidation state of metal: X+(-1)+(0)=0 X=+1 Irt+ Ligand: methyl anion, trimethylphosphine,. [Ir(C=C-Ph)(PME3)4] X(-1)+4(0)=+1 X-1=+1 X=+1 Irl+ Ligand: phenylacetylene anion, trimethyl phosphine Stability: [Ir(C=C-Ph)(PME3)4] is more stable due to phenylacetylene pi back bonding. So, [Ir(C=C-Ph)(PME3)4] is less stable compare to [IrMe(PMe3)4]
Expert Solution
steps

Step by step

Solved in 2 steps with 1 images

Blurred answer
Knowledge Booster
Coordination Complexes
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Principles of Modern Chemistry
Principles of Modern Chemistry
Chemistry
ISBN:
9781305079113
Author:
David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:
Cengage Learning
Chemistry: The Molecular Science
Chemistry: The Molecular Science
Chemistry
ISBN:
9781285199047
Author:
John W. Moore, Conrad L. Stanitski
Publisher:
Cengage Learning
Chemistry by OpenStax (2015-05-04)
Chemistry by OpenStax (2015-05-04)
Chemistry
ISBN:
9781938168390
Author:
Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:
OpenStax
Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
Chemistry
ISBN:
9781337399074
Author:
John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:
Cengage Learning
Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
Chemistry
ISBN:
9781133949640
Author:
John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:
Cengage Learning