A vendor is supplying 90 parts. Suppose that 10 of them are defective. We take a sample of size 6. At least 90% of the time the sample will contain k or fewer items. What is the smallest value of K?Give numerical answers as integers or decimals rounded to four decimal places.1. Notice here that the population size N = is known. We also know that M=. Let X be the number ofofthese are defective. We are taking a sample of size n3=defective items in the sample. Xhas a distribtuion.2. Notice that this is an inverse probability problem. We want to know the smallest value ofk where P(X s k) 0.9. Use Dr. Jackson's appropriate calculator function or programto solve this problem. The calculator returns the following portion of the CDF table.cdf(X)3. At least 90% of the time the sample will containk or fewer items. What is the value of k?Enter your answer in each of the answer boxes.O Type here to searchF12PriscrF9F10F11F4FS

Given data Total parts supplied by Vendors = 90 No of parts are defective = 10 Sample size = 6 1)…

Answered: A vendor is supplying 90 parts. Suppose…

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter5: Inverse, Exponential, And Logarithmic Functions

Section5.6: Exponential And Logarithmic Equations

Problem 64E

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A vending machine company wants to check three of its machines to determine if they are properly dispensing 12 ounces of coffee. Test by using α=0.05. Their data is given below. Machine A Machine B Machine C 11.8 11.7 12.2 12.1 11.9 12.1 12.0 11.7 12.0 11.9 11.8 11.9 12.1 12.0 12.2 Group of answer choices There is sufficient evidence to reject the claim that the proportions are equal because the p-value 0.0255 < 0.05 There is insufficient evidence to conclude the claim that the proportions are equal because the p-value 0.0255 < 0.05 There is insufficient evidence to reject the claim that the proportions are equal because the p-value 0.0255 < 0.05 There is sufficient evidence to conclude the claim that the proportions are equal because the p-value 0.0255 < 0.05
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A random sample of n = 12 individuals is selected from a population with μ = 70, and a treatment is administered to each individual in the sample. After treatment, the sample mean is found to be M = 74.5 with SS = 297.a. How much difference is there between the mean for the treated sample and the mean for the original population? (Note: In a hypothesis test, this value forms the numerator of the t statistic.)b. How much difference is expected just by chance between the sample mean and its population mean? That is, find the standard error for M. (Note: In a hypothesis test, this value is the denominator of the t statistic.)c. Based on the sample data, does the treatment have a significant effect? Use a two-tailed test with α = .05.
1) The desired percentage of SiO2 in a certain type of aluminous cement is 5.5. To test whether the true average percentage is 5.5 for a particular production facility, 16 independently obtained samples are analyzed. Suppose that the percentage of SiO2 in a sample is normally distributed with σ = 0.32 and that x = 5.21. (Use α = 0.05.) What value of n is required to satisfy α = 0.01 and β(5.6) = 0.01? (Round your answer up to the next whole number.) 2) Consider a paint-drying situation in which drying time for a test specimen is normally distributed with σ = 7. The hypotheses H0: μ = 74 and Ha: μ < 74 are to be tested using a random sample of n = 25 observations. The number of standard deviations (of X) below the null value x = 72.3 is 1.21. If x = 72.3, the conclusion using α = 0.003 : z = -1.21 P-value = 0.1123 If the test procedure with α = 0.003 is used, what n is necessary to ensure that β(70) = 0.01? (Round your answer up to the next whole number.)
The critical value for t for n = 10 for a one tail test at α = 5% LOS is

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