A voltaic cell was constructed using the following half-reactions: Th4+ (aq) + 4e - ---> E° = -1.899 V Mn2+ (aq) + 2e- ---> E° = -1.185 V -> Th(s) Mn(s) (a) The strongest reducing agent is (b) The Mn electrode will be (c) Which electrode will be the anode? (d) Which electrode will be the cathode? (e) What is the direction of electron flow? (f) Calculate the standard cell potential. (g) Determine Keq for the reaction of this voltaic cell. ( + and the strongest oxidizing agent is V ● "
A voltaic cell was constructed using the following half-reactions: Th4+ (aq) + 4e - ---> E° = -1.899 V Mn2+ (aq) + 2e- ---> E° = -1.185 V -> Th(s) Mn(s) (a) The strongest reducing agent is (b) The Mn electrode will be (c) Which electrode will be the anode? (d) Which electrode will be the cathode? (e) What is the direction of electron flow? (f) Calculate the standard cell potential. (g) Determine Keq for the reaction of this voltaic cell. ( + and the strongest oxidizing agent is V ● "
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter18: Electrochemistry
Section: Chapter Questions
Problem 18.49QE: A half-cell that consists of a copper wire in a 1.00 M Cu(NO3)2 solution is connected by a salt...
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