A W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression member. It is 7 m long, fixed at the top and bottom, and has additional support in the weak direction 3 m from the top. Properties of the section are: A = 14,500 mm² , Ix = 258.6 x 106 mm“, Iy = 84.375 x 106 mm* 1. Calculate the critical slenderness ratio of the member. A. 26.208 С. 36.706 В. 45.882 D. 27.529 2. Calculate the nominal axial load capacity of the column. A. 3 104 kN C. 4 213 kN B. 4 851 kN D.5 344 kN 3. that of the dead load. Use LRFD. Calculate the service axial dead load if the service axial live load is twice as A. 1 354 kN C. 1 093 kN B. 992 kN D. 634 kN

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter1: Tension, Compression, And Shear
Section: Chapter Questions
Problem 1.4.9P: Two steel wines support a moveable overhead camera weighing W = 28 lb (see figure part a) used For...
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NSCP 2015
Pn = FerAg
(505.3-1)
The flexural buckling stress, Fer, is determined as follows:
cr 5
KL
1. when
E
< 4.71
(or Fe 2 0.44F,)
r
Fy
Fer =
0.658Fe|
Fy
(505.3-2)
KL
E
> 4.71
( or F. < 0.44F,)
2. when
-
r
Fer = 0. 877F.
(505.3-3)
%3D
where
,= elastic critical buckling stress determined according
to Eq. 505.3-4, Section 505.4, or the provisions of
Section 503.2, as applicable, MPa.
e
Fe
(KL
(505.3-4)
(学)
2
A W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression
member. It is 7 m long, fixed at the top and bottom, and has additional support in
the weak direction 3 m from the top. Properties of the section are: A = 14,500
mm² , Ix = 258.6 x 10° mm“,
I, = 84.375 x 106 mm4
1.
Calculate the critical slenderness ratio of the member.
В. 45.882
A. 26.208
С. 36.706
D. 27.529
Calculate the nominal axial load capacity of the column.
A. 3 104 kN
C. 4 213 kN
2.
B. 4 851 kN
D.5 344 kN
3.
Calculate the service axial dead load if the service axial live load is twice as
that of the dead load. Use LRFD.
В. 992 kN
D. 634 kN
A. 1 354 kN
C. 1 093 kN
Transcribed Image Text:NSCP 2015 Pn = FerAg (505.3-1) The flexural buckling stress, Fer, is determined as follows: cr 5 KL 1. when E < 4.71 (or Fe 2 0.44F,) r Fy Fer = 0.658Fe| Fy (505.3-2) KL E > 4.71 ( or F. < 0.44F,) 2. when - r Fer = 0. 877F. (505.3-3) %3D where ,= elastic critical buckling stress determined according to Eq. 505.3-4, Section 505.4, or the provisions of Section 503.2, as applicable, MPa. e Fe (KL (505.3-4) (学) 2 A W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression member. It is 7 m long, fixed at the top and bottom, and has additional support in the weak direction 3 m from the top. Properties of the section are: A = 14,500 mm² , Ix = 258.6 x 10° mm“, I, = 84.375 x 106 mm4 1. Calculate the critical slenderness ratio of the member. В. 45.882 A. 26.208 С. 36.706 D. 27.529 Calculate the nominal axial load capacity of the column. A. 3 104 kN C. 4 213 kN 2. B. 4 851 kN D.5 344 kN 3. Calculate the service axial dead load if the service axial live load is twice as that of the dead load. Use LRFD. В. 992 kN D. 634 kN A. 1 354 kN C. 1 093 kN
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