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a. In an animal shelter, 100 cats and 50 dogs are being accommodated. Table below shows age gro cats and dogs. Dogs Cats Total Old 40 70 110 Young 10 30 40 Total 50 100 150 Test-statistics

a. In an animal shelter, 100 cats and 50 dogs are being accommodated. Table below shows age gro cats and dogs. Dogs Cats Total Old 40 70 110 Young 10 30 40 Total 50 100 150 Test-statistics

Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015
Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015
1st Edition
ISBN:9781680331141
Author:HOUGHTON MIFFLIN HARCOURT
Publisher:HOUGHTON MIFFLIN HARCOURT
Chapter9: Solving Quadratic Functions
Section: Chapter Questions
Problem 4CA
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a. In an animal shelter, 100 cats and 50 dogs are being accommodated. Table below shows age group of the cats and dogs. Dogs Cats Total Old 40 70 110 Young 10 30 40 Total 50 100 150 Test-statistics Z= -p) 0.8-0.7 /0.7333> |-0, =1. 3055 P-Value P – Value = 2 x P (Z > 1.3055) =2 x 0.0959 =0. 1918 Conclusion P-value 0.1918 is greater than the level of significance 0.05, therefore do not reject the null hypotheses. null hypotheses is accepted. Therefore the probability of being old in dogs and cats is equal. What is the power of the test in part a?
Transcribed Image Text:a. In an animal shelter, 100 cats and 50 dogs are being accommodated. Table below shows age group of the cats and dogs. Dogs Cats Total Old 40 70 110 Young 10 30 40 Total 50 100 150 Test-statistics Z= -p) 0.8-0.7 /0.7333> |-0, =1. 3055 P-Value P – Value = 2 x P (Z > 1.3055) =2 x 0.0959 =0. 1918 Conclusion P-value 0.1918 is greater than the level of significance 0.05, therefore do not reject the null hypotheses. null hypotheses is accepted. Therefore the probability of being old in dogs and cats is equal. What is the power of the test in part a?
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