а.Perform one sample calculation: to calculate AE in J and wavelength A in nm andcomplete the following table :Show one sample calculation431ΔΕAE =ΔΕ -ДЕ -AE =2.66x10-20 J1 = 7470 nmДЕ —ΔΕ-AE =AE =4AE =ДЕ —AE =XX3ДЕ —AE =XX=X2ΔΕ-XXXThen use the following table to determine the corresponding electronic transition:WavelengthColor656.2red486.1blue-green434.0blue-violet410.1violet2.

When the heat is provided, the electrons get excited from one energy level to the upper energy…

а. Perform one sample calculation: to calculate AE in J and wavelength A in nm and complete the following table : Show one sample calculation 5 4 3 2 1 6. AE = ΔΕ - AE = AE = AE = 2.66x10-20 J 1 = 7470 nm 5 AE = AE = AE = AE = X 4 ΔΕ - AE = AE = X X = 3 AE = AE = X X = X 2 ΔΕ- X X X X

а. Perform one sample calculation: to calculate AE in J and wavelength A in nm and complete the following table : Show one sample calculation 5 4 3 2 1 6. AE = ΔΕ - AE = AE = AE = 2.66x10-20 J 1 = 7470 nm 5 AE = AE = AE = AE = X 4 ΔΕ - AE = AE = X X = 3 AE = AE = X X = X 2 ΔΕ- X X X X

Inquiry into Physics

8th Edition

ISBN:9781337515863

Author:Ostdiek

Publisher:Ostdiek

Chapter10: Atomic Physics

Section: Chapter Questions

Problem 1C

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Concept explainers

Wien's displacement law

Students often get confused between Wien's displacement law and Planck's radiation law. Although both are historically related, yet they are conceptually different. Planck's law helps determine the spectrum of a blackbody, while Wien's law determines the relationship between peak wavelength and temperature.

Question

а.
Perform one sample calculation: to calculate AE in J and wavelength A in nm and
complete the following table :
Show one sample calculation
4
3
1
ΔΕ
AE =
ΔΕ -
ДЕ -
AE =
2.66x10-20 J
1 = 7470 nm
ДЕ —
ΔΕ-
AE =
AE =
4
AE =
ДЕ —
AE =
X
X
3
ДЕ —
AE =
X
X
=
X
2
ΔΕ-
X
X
X
Then use the following table to determine the corresponding electronic transition:
Wavelength
Color
656.2
red
486.1
blue-green
434.0
blue-violet
410.1
violet
2.

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