A. Rearrange the data in step 1c. from highest to lowest numbers. (Put a space between each pairs of numbers.) B. Label the Parentals (= the pair of numbers that are the most frequent) versus Recombinants. C. Further subdivide recombinants as single crossovers region 1", single crossovers region 2*, double crossovers (-least frequent). [*note: single cross overs are the two pairs that are intermediate between parentals and double cross overs.] and
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- Part 2: Data Tables Table 1: Parent Genotypes: Monohybrid Crosses Generation Genotype of Individual #1 Genotype of Individual #2 P Yy Ss P1 Yy Ss P2 Yy ss P3 Yy SS P4 YY SS Table 2: Generation Data Produced by Monohybrid Crosses Generation Possible Offspring Genotypes Possible Offspring Phenotypes Genotype Ratio Phenotype Ratio P yySs P1 yySs P2 Yyss P3 YySS P4 YYSS Part 2: Post-Lab Questions How much genotypic variation do you find in the randomly picked parents of your crosses? How much in the offspring? Pool all of the offspring from your five replicates. How much phenotypic variation do you find? Is the ratio of observed phenotypes the same as the ratio of predicted phenotypes? Why or why not? What is the difference between genes and alleles? How might protein synthesis execute differently if a mutation occurs?…Topic: Trihybrid Cross, Height in merigonias is determined by three unlinked genes that act additively. Each has two alleles, one compltely dominant allele(A,B or C) that makes plants taller and one recessive allele that makes plants shorter. Do the corss AaBbCc X AaBbCc. The fraction of The F1 progenty will be ? Pls explain it with more details. thanksInterpret the result of your Chi-squared test. How many gene pairs were responsible for eye color in flies as associated with sex? What gene interaction was present in the gene/s for eye color? What is the genotype of the possible P1 & P2 that produced this F2 population? (Remember to indicate your gene notation).
- 1)A researcher crossed a homozygous yellow seed plant (YY) and a heterozygous yellowseed plant (Yy). Draw a Punnett Square and determine the genotype and phenotyperatios of the offspring. please explain it simple and no copypastes thanksWhile sitting at home during Movement Control Order (MCO) because of pandemic covid19, observe two different traits of a couple in your family (eg. your mom & dad or your sister & her husband or your brother & his wife, etc). Draw a genetic cross that involves cross of the parents with the chosen 2 pairs of their contracting traits. Imagine that the cross obeys the Mendelian Laws, show the cross and gametes production for each generation (P, F1 and F2). By Using a Punnet square as symbolic representation of the results for the cross, determine the phenotypes, genotypes, phenotypic ratio and genotypic ratio of F2 generation in the family.Activity 9GENES SEGREGATION BY BEAN-O TYPE Materials: Colored beans to represent the gene for a certain trait of garden pea. (60 pieces of the same size and shape; 30 pieces of which are of different colors from rest) Procedures: 1. Place the 30 pieces beans (one color) to one container and the other 30 pieces to the other container. Assign which color of beans will represent dominant and recessive genes of a specific trait of garden pea 2. Label the paper container as First Parent P1, male and other P1 female 3. At random, segregate the beans on the Lab table. Assume fertilization occurs and First filial generations (F1) are formed 4. Categorize the formed First filial generations 5. Put all the beans in one container. Assume that all the first filial generations undergo self-fertilization 6. Pick up the beans by two from the container without looking at it and collect the second Filial generation (F2) 7. Categorize the formed Second filial generations into two (2) phenotype, and…
- . Consider the genotypes of two lines of chickens: thepure-line mottled Honduran is i/i ; D/D ; M/M ; W/W, andthe pure-line leghorn is I/I ; d/d ; m/m ; w/w, whereI = white feathers, i = colored feathersD = duplex comb, d = simplex combM = bearded, m = beardlessW = white skin, w = yellow skinThese four genes assort independently. Starting withthese two pure lines, what is the fastest and mostconvenient way of generating a pure line that has coloredfeathers, has a simplex comb, is beardless, and has yellowskin? Make sure that you showa. the breeding pedigree.b. the genotype of each animal represented.c. how many eggs to hatch in each cross, and why thisnumber.d. why your scheme is the fastest and the mostconvenientUsing the data on the segregation of eye-color from Dosophila culture (see table 1). Tabulate your F1 and F2 data on eye-color as associated with sex by making a table. Based on your observations, frame your hypothesis as to the expected segregation of eye-color associated with sex. Apply the Chi-squared test to determine the goodness of fit of your data per generation. Ho: Ha: Decision Criteria: If X2c < X2tab, accept Ho. Otherwise, fail to accept Ho and accept Ha. Fill-up the next table. Conclusion:select whcih ic correct When 2 wildtype alleles are on the same parental chromosome, this is known as [Combined or Coupling or dispersed or heterozygous or Repulsion] . In sharp contrast [Combined or Coupling or dispersed or heterozygous or Repulsion] is when 1 wildtype allele and 1 mutant allele are on the same parental chromosome
- With two pairs of genes involved (P/p and Z/z), atestcross (ppzz) with an organism of unknown genotypeindicated that the gametes produced were in the followingproportionsPZ, 42.4%; Pz, 6.9%; pZ, 7.1%; pz, 43.6%Draw all possible conclusions from these data.please choose correct letter and discuss why you choose it.thanks 1. which among the statements about genetic correlation is true? a. always positive b. closely linked genes tend to stay together over several generations c. shown when genes have high penetrance d. none of the above 2. The part of the genotypic value that can be directly transmitted from parents to offspring? a. breeding value b. gene combination value c.environmental value d. none of the aboveTopic: Trihybrid Cross, Height in merigonias is determined by three unlinked genes that act additively. Each has two alleles, one compltely dominant allele(A,B or C) that makes plants taller and one recessive allele that makes plants shorter. Do the corss AaBbCc X AaBbCc. The F1 progenty: 27/64 will be as tall as the parents; 37/64 will be shorter than the parents. Pls explain it with more details. thanks