STOICHIΟΜΕTRYA. Use the equation to calculate the following:2 NaOH(aq) + H,SO4(aq) → Na,SO,(aq) + 2 H,O(1)#1 - the moles N22SO4 produced from 3.6 mol H2SO4the moles NaOH required to react with 2.50 L of 0.125 M H2SO4#3 - the volume of 0.250 M H2SO4 needed to react with 25.5 mL of 0.750 M NAOH#2

1. From the reaction it is clear that one mole of Na2SO4 is obtained from one mole of H2SO4. So, 3.6…

A. Use the equation to calculate the following: 2 NaOH(aq) + H,SO4(aq) → Na,SO,(aq) + 2 H,O(1) the moles Na2SO4 produced from 3.6 mol H2SO4 #2 - the moles NaOH required to react with 2.50 L of 0.125 M H2SO4 #3 - the volume of 0.250 M H2SO4 needed to react with 25.5 mL of 0.750 M NAOH

A. Use the equation to calculate the following: 2 NaOH(aq) + H,SO4(aq) → Na,SO,(aq) + 2 H,O(1) the moles Na2SO4 produced from 3.6 mol H2SO4 #2 - the moles NaOH required to react with 2.50 L of 0.125 M H2SO4 #3 - the volume of 0.250 M H2SO4 needed to react with 25.5 mL of 0.750 M NAOH

Introductory Chemistry: A Foundation

9th Edition

ISBN:9781337399425

Author:Steven S. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Donald J. DeCoste

Chapter15: Solutions

Section: Chapter Questions

Problem 87QAP: 87. What volume of 0.151 N NaOH is required to neutralize 24.2 mL of 0.125 N H2SO4? What volume of...

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Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.

Question

STOICHIΟΜΕTRY
A. Use the equation to calculate the following:
2 NaOH(aq) + H,SO4(aq) → Na,SO,(aq) + 2 H,O(1)
#1 - the moles N22SO4 produced from 3.6 mol H2SO4
the moles NaOH required to react with 2.50 L of 0.125 M H2SO4
#3 - the volume of 0.250 M H2SO4 needed to react with 25.5 mL of 0.750 M NAOH
#2

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