According to a 2018 survey of student loan debt incurred to finance undergraduate education, the statistics are: X̅ = $25,786.74, the presumed population standard deviation is $9,155.70, and n = 1,000. Please Note: The t-value with 999 degrees of freedom is 1.962. G)Which standardized score is more appropriate: z-values or student-t? Explain your answer. H)What would happen to the confidence interval if you changed the level of confidenceto 99%? I)Whatwould happen to the confidence interval if you increase the sample size?
According to a 2018 survey of student loan debt incurred to finance undergraduate education, the statistics are: X̅ = $25,786.74, the presumed population standard deviation is $9,155.70, and n = 1,000. Please Note: The t-value with 999 degrees of freedom is 1.962. G)Which standardized score is more appropriate: z-values or student-t? Explain your answer. H)What would happen to the confidence interval if you changed the level of confidenceto 99%? I)Whatwould happen to the confidence interval if you increase the sample size?
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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According to a 2018 survey of student loan debt incurred to finance undergraduate
education, the statistics are: X̅ = $25,786.74, the presumed population standard
deviation is $9,155.70, and n = 1,000. Please Note: The t-value with 999 degrees of freedom is 1.962.
G)Which standardized score is more appropriate: z-values or student-t? Explain your answer.
- H)What would happen to the confidence interval if you changed the level of confidenceto 99%?
- I)Whatwould happen to the confidence interval if you increase the
sample size ?
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