According to a survey in a country, 24% of adults do not own a credit card. Suppose a simple random sample of 900 adults is obtained. Complete parts (a) through (d) below. (a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below. O A. Not normal because ns0.05N and np(1-p)<10 O B. Not normal because ns 0.05N and np(1-p)2 10 O C. Approximately normal because ns0.05N and np(1 -p)< 10 O D. Approximately normal because n<0.05N and np(1-p)2 10 Determine the mean of the sampling distribution of p. HA = (Round to two decimal places as needed.) Determine the standard deviation of the sampling distribution of p. OA = (Round to three decimal places as needed.) (b) What is the probability that in a random sample of 900 adults, more than 27% do not own a credit card? The probability is (Round to four decimal places as needed.) (c) What is the probability that in a random sample of 900 adults, between 22% and 27% do not own a credit card? The probability is (Round to four decimal places as needed.)

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section11.4: Collecting Data
Problem 5E
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According to a survey in a country, 24% of adults do not own a credit card. Suppose a simple random sample of 900 adults is obtained. Complete parts (a) through (d) below.
(a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below.
O A. Not normal because ns0.05N and np(1-p)<10
O B. Not normal because ns 0.05N and np(1-p)2 10
O C. Approximately normal because ns0.05N and np(1 -p)< 10
O D. Approximately normal because n<0.05N and np(1-p)2 10
Determine the mean of the sampling distribution of p.
HA =
(Round to two decimal places as needed.)
Determine the standard deviation of the sampling distribution of p.
OA =
(Round to three decimal places as needed.)
(b) What is the probability that in a random sample of 900 adults, more than 27% do not own a credit card?
The probability is
(Round to four decimal places as needed.)
(c) What is the probability that in a random sample of 900 adults, between 22% and 27% do not own a credit card?
The probability is
(Round to four decimal places as needed.)
Transcribed Image Text:According to a survey in a country, 24% of adults do not own a credit card. Suppose a simple random sample of 900 adults is obtained. Complete parts (a) through (d) below. (a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below. O A. Not normal because ns0.05N and np(1-p)<10 O B. Not normal because ns 0.05N and np(1-p)2 10 O C. Approximately normal because ns0.05N and np(1 -p)< 10 O D. Approximately normal because n<0.05N and np(1-p)2 10 Determine the mean of the sampling distribution of p. HA = (Round to two decimal places as needed.) Determine the standard deviation of the sampling distribution of p. OA = (Round to three decimal places as needed.) (b) What is the probability that in a random sample of 900 adults, more than 27% do not own a credit card? The probability is (Round to four decimal places as needed.) (c) What is the probability that in a random sample of 900 adults, between 22% and 27% do not own a credit card? The probability is (Round to four decimal places as needed.)
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