According to recent research, 34% of Americans have less than $450 in the bank for an emergency. Let be hat p the proportion of people who have less than $450 in the bank for an emergency in a random sample of 91 Americans . Determine the probability that the proportion of people in a random sample of 91 Americans who have less than $450 in the bank for an emergency is within 2% of the population proportion. Round the solution to four decimal places . within 2% of the population proportion)= Box Determine the probability that the proportion of people in a random sample of 91 Americans who have less than $450 in the bank for an emergency is less than the population proportion by 9% or more. Round the solution to four decimal places . P( hat p less than the population proportion by 9\% or more)

College Algebra
10th Edition
ISBN:9781337282291
Author:Ron Larson
Publisher:Ron Larson
Chapter8: Sequences, Series,and Probability
Section: Chapter Questions
Problem 41CT: On a game show, a contestant is given the digits 3, 4, and 5 to arrange in the proper order to form...
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According to recent research, 34% of Americans have less than $450 in the bank for an emergency. Let be hat p the proportion of people who have less than $450 in the bank for an emergency in a random sample of 91 Americans . Determine the probability that the proportion of people in a random sample of 91 Americans who have less than $450 in the bank for an emergency is within 2% of the population proportion. Round the solution to four decimal places . within 2% of the population proportion)= Box Determine the probability that the proportion of people in a random sample of 91 Americans who have less than $450 in the bank for an emergency is less than the population proportion by 9% or more. Round the solution to four decimal places . P( hat p less than the population proportion by 9\% or more) 

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