Adapt the method of Example 6 to determine the amplitude, period, and phase shift for the given function. Graph the function over one period indicating the x- intercepts and the coordinates of the highest and lowest points on the graph. (a) y= 3 cos( - 2x)

Principles of Physics: A Calculus-Based Text
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Chapter12: Oscillatory Motion
Section: Chapter Questions
Problem 30P: A small object is attached to the end of a string to form a simple pendulum. The period of its...
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(ь)
= sin(-2mx - 1)
amplitude
period
phase shift
y
8.
4
8
4
8.
8.
4
8
2,
y
7.
2
1
1
1
1
8.
4
8
4
8.
4
x-intercepts
(x, y) =
(smallest x-value)
(x, y) =
(x, y) =
(largest x-value)
highest point
(x, y) =
lowest point
(x, y) =
1I2
Transcribed Image Text:(ь) = sin(-2mx - 1) amplitude period phase shift y 8. 4 8 4 8. 8. 4 8 2, y 7. 2 1 1 1 1 8. 4 8 4 8. 4 x-intercepts (x, y) = (smallest x-value) (x, y) = (x, y) = (largest x-value) highest point (x, y) = lowest point (x, y) = 1I2
Adapt the method of Example 6 to determine the amplitude, period, and phase shift for the given function. Graph the function over one period indicating the x-
intercepts and the coordinates of the highest and lowest points on the graph.
(a) y = 3 cos(7 - 2x)
amplitude
period
phase shift
y
y
3-
3
3
3
5/7
Зя
4
4
4
4
4
2
o-3
y
4.
4
2
x-intercepts
(х, у) -
(smaller x-value)
(х, у) -
(larger x-value)
highest points (x, y) =
(smaller x-value)
(x, y) =
(larger x-value)
lowest point
(x, y) =
Transcribed Image Text:Adapt the method of Example 6 to determine the amplitude, period, and phase shift for the given function. Graph the function over one period indicating the x- intercepts and the coordinates of the highest and lowest points on the graph. (a) y = 3 cos(7 - 2x) amplitude period phase shift y y 3- 3 3 3 5/7 Зя 4 4 4 4 4 2 o-3 y 4. 4 2 x-intercepts (х, у) - (smaller x-value) (х, у) - (larger x-value) highest points (x, y) = (smaller x-value) (x, y) = (larger x-value) lowest point (x, y) =
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